mL g kg (0.25 D (1-²) (114) (1). (² 3 mL 3 10 L 10³ g = 0.29 kg

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A student sets up and solves the following equation to solve a problem in solution stoichiometry.

Fill in the missing part of the student's equation.

mL
g
1 kg
(0.25D (1-²) (1.14 ± ) ( ) - 0
:)
=
3
mL
10
L
10³
g
3
0.29 kg
Transcribed Image Text:mL g 1 kg (0.25D (1-²) (1.14 ± ) ( ) - 0 :) = 3 mL 10 L 10³ g 3 0.29 kg
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