Answered: min 4a1 + 5xз subject to 2x1 + x2 – 5x3…

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min 4a1 + 5xз subject to 2x1 + x2 – 5x3 -3x1 = 1 + 4xз + х4 — 2 Ti > 0,і — 1,2, 3, 4.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

Consider the LP Problem (attached image):

(a) Find an optimal solution using the simplex method. Is it unique?

(b) Write down the dual problem and find an optimal solution. Is it unique?

(c) Suppose now that the vector b = (1, 2) is changed to (−1, −1). Find an optimal solution and the value of the optimal cost.

4x1 + 5x3
2x1 + x2 – 5x3
-3x1
subject to
= 1
+ 42з + х4 — 2
Ti 2 0, i = 1, 2, 3, 4.

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