Solve the given problem using the simplex method. Minimize: C = 5x +6y Subject to: x + y = 1000 x <= 300 y >= 150 x, y >= 0 Entering variable from Table 1: Entering variable from Table 2: Leaving variable from Table 1: Value of the pivot element in Table 3: Total cost in table 3: Value of y in the optimal table: Leaving variable from Table 3: Total cost in table 2: Value of the pivot element in Table 2: Leaving variable from Table 2: Value of the pivot element in Table

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Solve the given problem using the simplex method.
Minimize: C = 5x +6y
Subject to:
x + y = 1000
x <= 300
y >= 150
x, y >= 0

Entering variable from Table 1:

Entering variable from Table 2:

Leaving variable from Table 1:

Value of the pivot element in Table 3:

Total cost in table 3:

Value of y in the optimal table:

Leaving variable from Table 3:

Total cost in table 2:

Value of the pivot element in Table 2:

Leaving variable from Table 2:

Value of the pivot element in Table 1:

Value of x in the optimal table:

Minimum cost:

Total cost in table 1:

Entering variable from Table 3:

Table 1
10
10
PROD
QTY
S1
S2
A1
A2
10
A1
1000
300
1
1
1
51
1
10
A2
150
-1
1
Zj
Cj - Zj
10
20
-10
10
10
Table 2
6
10
10
PROD
QTY
s1
S2
A1
A2
1
1
-1
1
-1
1
Zj
Cj - Zj
10
10
-4
Table 3
Cj
6
10
10
PROD
QTY
S2
A1
A2
-1
1
1
-1
1
1
-1
1
Zj
C- Z
6
-5
4
10
-4
Table 4
10
10
PROD
QTY
s1
S2
A1
A2
-1
1
1
-1
1
-1
Zj
Cj - Zj
6
-1
1
4
10
Transcribed Image Text:Table 1 10 10 PROD QTY S1 S2 A1 A2 10 A1 1000 300 1 1 1 51 1 10 A2 150 -1 1 Zj Cj - Zj 10 20 -10 10 10 Table 2 6 10 10 PROD QTY s1 S2 A1 A2 1 1 -1 1 -1 1 Zj Cj - Zj 10 10 -4 Table 3 Cj 6 10 10 PROD QTY S2 A1 A2 -1 1 1 -1 1 1 -1 1 Zj C- Z 6 -5 4 10 -4 Table 4 10 10 PROD QTY s1 S2 A1 A2 -1 1 1 -1 1 -1 Zj Cj - Zj 6 -1 1 4 10
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