Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7 Hg O3, with methanol, CH3 OH. C7 H6O3 + CH3 OH → C3 Hg O3 + H2O In an experiment, 1.20 g of salicylic acid is reacted with 14.5 g of methanol. The yield of methyl salicylate, CsHs O3, is 1.02 g. What is the percentage yield? Percentage yield = %3D
Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7 Hg O3, with methanol, CH3 OH. C7 H6O3 + CH3 OH → C3 Hg O3 + H2O In an experiment, 1.20 g of salicylic acid is reacted with 14.5 g of methanol. The yield of methyl salicylate, CsHs O3, is 1.02 g. What is the percentage yield? Percentage yield = %3D
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Chapter3: Calculations With Chemical Formulas And Equaitons
Section: Chapter Questions
Problem 3.98QP: Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7H6O3, with methanol,...
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Question
![Methyl salicylate (oil of wintergreen) is prepared by heating
salicylic acid,
C7 H6 O3, with methanol,
CH3 OH.
C7H; O3 + CH3OH → C3H3 O3 +H2O
In an experiment, 1.20 g of salicylic acid is reacted with
14.5 g of methanol. The yield of methyl salicylate, C3 Hs O3,
is 1.02 g. What is the percentage yield?
Percentage yield
%
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa8d3fce-d16d-4f4d-b492-1dee716a707b%2Fea5218e8-712c-4521-9111-e477d2511bfb%2Fvi4v9t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Methyl salicylate (oil of wintergreen) is prepared by heating
salicylic acid,
C7 H6 O3, with methanol,
CH3 OH.
C7H; O3 + CH3OH → C3H3 O3 +H2O
In an experiment, 1.20 g of salicylic acid is reacted with
14.5 g of methanol. The yield of methyl salicylate, C3 Hs O3,
is 1.02 g. What is the percentage yield?
Percentage yield
%
%3D
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