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method used for the iron cube. Because the heaters were linked, determine the specific heat of the brick, Cbr. that e raised from Ti to T= 150°C.The specific heat of iron is 00 Click on "Energy Symbols" and “Link Heaters". Heat both cubes reaches Tre = 150°C, quickly release the heat slider and click on If you overshoot, you can cool the cubes down by moving the Calculate the amount of energy the iron cube will absotb whe the total energy absorbed by each cube is the same: Use the values of mbr, QFe and Tor from the previous calculations to until the iron reaches TFe = 150°C. When the iron cube Calculate the specific heat Cbr for the brick, using the same Qor = MbrCorAT = mbrCbr(Tbr - Ti) = QFe Lab 11 Ins Due: See Cou. : mc 4T Q:MCAT 1-massinly 7-heat transtr T-Chang b. in temp Answer: e 19/amo emse e is u the Pause button. slider down or you can just let the heat dissipate and Pause the experiment when you get to the desired temperature. If you need to repeat the measurement, click the orange Reset button and start fresh with both cubes at room temperature (i.e., the first tick mark) ons bnste C. When the iron cube reaches TFe = 150°C, what is the temperature of the brick cube? Answer: d. %3D %3D QFe = mbrCbr(Tbr T) Oor = QFe/[mbr(Tbr Till %3D Answer:

method used for the iron cube. Because the heaters were linked, determine the specific heat of the brick, Cbr. that e raised from Ti to T= 150°C.The specific heat of iron is 00 Click on "Energy Symbols" and “Link Heaters". Heat both cubes reaches Tre = 150°C, quickly release the heat slider and click on If you overshoot, you can cool the cubes down by moving the Calculate the amount of energy the iron cube will absotb whe the total energy absorbed by each cube is the same: Use the values of mbr, QFe and Tor from the previous calculations to until the iron reaches TFe = 150°C. When the iron cube Calculate the specific heat Cbr for the brick, using the same Qor = MbrCorAT = mbrCbr(Tbr - Ti) = QFe Lab 11 Ins Due: See Cou. : mc 4T Q:MCAT 1-massinly 7-heat transtr T-Chang b. in temp Answer: e 19/amo emse e is u the Pause button. slider down or you can just let the heat dissipate and Pause the experiment when you get to the desired temperature. If you need to repeat the measurement, click the orange Reset button and start fresh with both cubes at room temperature (i.e., the first tick mark) ons bnste C. When the iron cube reaches TFe = 150°C, what is the temperature of the brick cube? Answer: d. %3D %3D QFe = mbrCbr(Tbr T) Oor = QFe/[mbr(Tbr Till %3D Answer:

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until the iron reaches TFe = 150°C. When the iron cube reaches TFe = 150°C, quickly release the heat slider and click on determine the specific heat of the brick, Cbr. Click on "Energy Symbols" and “Link Heaters". Heat both cubes Qbr = mbrCbrAT = mbrCbr( Tbr - T;) = QFe Calculate the specific heat Cbr for the brick, using the same method used for the iron cube. Because the heaters were linked, the total energy absorbed by each cube is the same: Use the values of mbr, QFe and Tbr from the previous calculations to Lab 11 Instr ent ee. 9-mc 4T mc AT Answer: lenstem 1001 emse en M-mas s Q-heat transtr = 130 the Pause button. If vou overshoot, you can cool the cubes down by moving the slider down or you can just let the heat dissipate and Pause the experiment when you get to the desired temperature. If you need to repeat the measurement, click the orange Reset button and start fresh with both cubes at room temperature (i.e., the first tick mark) janaoy C. When the iron cube reaches TFe = 150°C, what is the temperature of the brick cube? Answer: d. %3D %3D QFe = mbrCbr(Tbr- Ti) Cor = QFe/[mbr(Tbr - Answer:
Transcribed Image Text:until the iron reaches TFe = 150°C. When the iron cube reaches TFe = 150°C, quickly release the heat slider and click on determine the specific heat of the brick, Cbr. Click on "Energy Symbols" and “Link Heaters". Heat both cubes Qbr = mbrCbrAT = mbrCbr( Tbr - T;) = QFe Calculate the specific heat Cbr for the brick, using the same method used for the iron cube. Because the heaters were linked, the total energy absorbed by each cube is the same: Use the values of mbr, QFe and Tbr from the previous calculations to Lab 11 Instr ent ee. 9-mc 4T mc AT Answer: lenstem 1001 emse en M-mas s Q-heat transtr = 130 the Pause button. If vou overshoot, you can cool the cubes down by moving the slider down or you can just let the heat dissipate and Pause the experiment when you get to the desired temperature. If you need to repeat the measurement, click the orange Reset button and start fresh with both cubes at room temperature (i.e., the first tick mark) janaoy C. When the iron cube reaches TFe = 150°C, what is the temperature of the brick cube? Answer: d. %3D %3D QFe = mbrCbr(Tbr- Ti) Cor = QFe/[mbr(Tbr - Answer:
Lab 11 Instructions: Specific Heat Due: See Course Schedule nnw c.bedThe bottom-most (first) ticku markeronsthe thermometer 00 2 no corresponds to the initial room temperature, Ti and the forth tick no corresponds to T = 100°C? What is the value of each tick mark? Answer: 20°C Now, that the thermometer is calibrated we can read the temperature of the other materials. We'll assume everything in -m the room starts out at the same room temperature, T: (in Celsius 2ede tod degrees). saH niJ" bns "elo edu nori ərlt nerdW O 2 T aerlaser noti erli liinu Determine the Specific Heat eloybloiup, 0a Teerlo591 nottud eeue9 gd 1.3 To find the specific heat of the brick and the oil, we need to figure out erl eexactly how much heat energy we are adding when the heat slider on the bucket is moved. nenw inemheqxe Jeas The heat slider isn't calibrated, but we can link the heaters, which means they will generate identical heat output for both buckets. So if we place the iron on one stand, and the brick on the other one, they will receive the same amount of energy when we turn up the heat. Now we only need to figure out how much energy one of the cube absorbs. e.i) eni Volume brioK 103 phd eri 1ol E Sisece emsa en pniau .benil anew 1oleer seueo08 o noni orit hal beau borttem temea ei eduo dose E bedioads vpmene istol arl Brick Iron n to eeole eaU of and Water Olive Oil Heat Heat Cool Cool Page 5 of 9 nts
Transcribed Image Text:Lab 11 Instructions: Specific Heat Due: See Course Schedule nnw c.bedThe bottom-most (first) ticku markeronsthe thermometer 00 2 no corresponds to the initial room temperature, Ti and the forth tick no corresponds to T = 100°C? What is the value of each tick mark? Answer: 20°C Now, that the thermometer is calibrated we can read the temperature of the other materials. We'll assume everything in -m the room starts out at the same room temperature, T: (in Celsius 2ede tod degrees). saH niJ" bns "elo edu nori ərlt nerdW O 2 T aerlaser noti erli liinu Determine the Specific Heat eloybloiup, 0a Teerlo591 nottud eeue9 gd 1.3 To find the specific heat of the brick and the oil, we need to figure out erl eexactly how much heat energy we are adding when the heat slider on the bucket is moved. nenw inemheqxe Jeas The heat slider isn't calibrated, but we can link the heaters, which means they will generate identical heat output for both buckets. So if we place the iron on one stand, and the brick on the other one, they will receive the same amount of energy when we turn up the heat. Now we only need to figure out how much energy one of the cube absorbs. e.i) eni Volume brioK 103 phd eri 1ol E Sisece emsa en pniau .benil anew 1oleer seueo08 o noni orit hal beau borttem temea ei eduo dose E bedioads vpmene istol arl Brick Iron n to eeole eaU of and Water Olive Oil Heat Heat Cool Cool Page 5 of 9 nts
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