College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please type out and or diagram Your solution in a way that is easy to read I have bad eyesight
![**Question 18: (I)**
A heat engine exhausts 8200 J of heat while performing 2600 J of useful work. What is the efficiency of this engine?
**Solution:**
To find the efficiency of a heat engine, you can use the formula:
\[ \text{Efficiency} (\eta) = \frac{\text{Useful Work Output}}{\text{Total Heat Input}} \times 100\% \]
In this case:
- The useful work output \( W = 2600 \text{ J} \)
- The total heat input \( Q = W + \text{Heat Exhausted} \)
So,
\[ Q = 2600 \text{ J} + 8200 \text{ J} = 10800 \text{ J} \]
Then the efficiency (\(\eta\)) is:
\[ \eta = \frac{2600 \text{ J}}{10800 \text{ J}} \times 100\% \]
\[ \eta = \frac{2600}{10800} \times 100\% \]
\[ \eta \approx 24.07\% \]
Therefore, the efficiency of this engine is approximately 24.07%.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F945fb729-18ab-4cd1-bab9-1cd947509b50%2Fe0eda18c-c351-435b-a320-b273c56f9a0e%2Fr1sxt3_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 18: (I)**
A heat engine exhausts 8200 J of heat while performing 2600 J of useful work. What is the efficiency of this engine?
**Solution:**
To find the efficiency of a heat engine, you can use the formula:
\[ \text{Efficiency} (\eta) = \frac{\text{Useful Work Output}}{\text{Total Heat Input}} \times 100\% \]
In this case:
- The useful work output \( W = 2600 \text{ J} \)
- The total heat input \( Q = W + \text{Heat Exhausted} \)
So,
\[ Q = 2600 \text{ J} + 8200 \text{ J} = 10800 \text{ J} \]
Then the efficiency (\(\eta\)) is:
\[ \eta = \frac{2600 \text{ J}}{10800 \text{ J}} \times 100\% \]
\[ \eta = \frac{2600}{10800} \times 100\% \]
\[ \eta \approx 24.07\% \]
Therefore, the efficiency of this engine is approximately 24.07%.
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