Methane (CH, M = 16 g/mol) flows through a gas pipeline at a rate of 48 Ibm/h. If the gas is maintained at 86 °F and 17.8 psia. a. Find the volumetric flow rate of CH. using the ideal gas law. b. Find the volumetric flow rate of CHa using the combined gas law. At STP, 1 lb-mol of gas has a volume of 359 ft'. c. Find the flow rate in standard cubic feet per hour (SCFH). The SCFH is defined as the hypothetical volumetric flow rate in ft'/h if the same moles of gas were at STP.
Methane (CH, M = 16 g/mol) flows through a gas pipeline at a rate of 48 Ibm/h. If the gas is maintained at 86 °F and 17.8 psia. a. Find the volumetric flow rate of CH. using the ideal gas law. b. Find the volumetric flow rate of CHa using the combined gas law. At STP, 1 lb-mol of gas has a volume of 359 ft'. c. Find the flow rate in standard cubic feet per hour (SCFH). The SCFH is defined as the hypothetical volumetric flow rate in ft'/h if the same moles of gas were at STP.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![Methane (CH«, M = 16 g/mol) flows through a gas pipeline at a rate of 48 Ibm/h. If the gas is maintained at 86 °F and
17.8 psia.
a. Find the volumetric flow rate of CHa using the ideal gas law.
b. Find the volumetric flow rate of CH, using the combined gas law. At STP, 1 lb-mol of gas has a volume of 359 ft.
C. Find the flow rate in standard cubic feet per hour (SCFH). The SCFH is defined as the hypothetical volumetric flow
rate in ft/h if the same moles of gas were at STP.
Solution:
For item (a):
The ideal gas law uses the moles instead of mass. Convert the mass flow rate to a molar flow rate.
M
Use the ideal gas law to solve for the volumetric flow rate. We use R = 10.73 ft²-psi/lb-mol-°R because of its compatibility
with the other units. Convert "F to "R using T(°R] = T[°F] + 459.67.
RT
pV = ńRT → V =.
For item (b):
The combined gas law is shown below. At STP (1 atm = 14.7 psi pressure and 0 "C = 491.67 "R temperature), the
volumetric flow rate of 1 Ib-mol/h of gas is 359 ft²/h. Note that n and T (for the actual conditions) have been computed
previously in Item (a).
pV PStpVSTP (17.8 psi)V
(14.7 psi)(359 ft /h)
(1 lb-mol/h)(491.67 °R)
V =
For item (c):
The flow rate in SCFH is the hypothetical volumetric flow rate VSCFH if the same moles of gas in actual conditions i were
subjected to the pressure and temperature at STP (PsTP = 14.7 psi, TSTp = 491.67 °R). When asked to report the flow rate
in SCFH, replace the "ft°/h" unit with "SCFH" (ie., "1 SCFH").
PSTpVscau = iRTSTp → Vaczu = ARTSTP
PSTP
Note that Vscen is different from VSTP. VSTP is always paired with iStp = 1 lb-mol/h in AES units (or Vsrp = 22.4 L
when nSTp = 1 mol in Sl units), whereas Vscru Uses the true or actual molar flow rate n.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05785e48-814d-4dc6-a6cd-8b0dba827f0d%2Fd742a6b4-1aef-43ee-8548-22faacc69894%2Fyl2nhvt_processed.png&w=3840&q=75)
Transcribed Image Text:Methane (CH«, M = 16 g/mol) flows through a gas pipeline at a rate of 48 Ibm/h. If the gas is maintained at 86 °F and
17.8 psia.
a. Find the volumetric flow rate of CHa using the ideal gas law.
b. Find the volumetric flow rate of CH, using the combined gas law. At STP, 1 lb-mol of gas has a volume of 359 ft.
C. Find the flow rate in standard cubic feet per hour (SCFH). The SCFH is defined as the hypothetical volumetric flow
rate in ft/h if the same moles of gas were at STP.
Solution:
For item (a):
The ideal gas law uses the moles instead of mass. Convert the mass flow rate to a molar flow rate.
M
Use the ideal gas law to solve for the volumetric flow rate. We use R = 10.73 ft²-psi/lb-mol-°R because of its compatibility
with the other units. Convert "F to "R using T(°R] = T[°F] + 459.67.
RT
pV = ńRT → V =.
For item (b):
The combined gas law is shown below. At STP (1 atm = 14.7 psi pressure and 0 "C = 491.67 "R temperature), the
volumetric flow rate of 1 Ib-mol/h of gas is 359 ft²/h. Note that n and T (for the actual conditions) have been computed
previously in Item (a).
pV PStpVSTP (17.8 psi)V
(14.7 psi)(359 ft /h)
(1 lb-mol/h)(491.67 °R)
V =
For item (c):
The flow rate in SCFH is the hypothetical volumetric flow rate VSCFH if the same moles of gas in actual conditions i were
subjected to the pressure and temperature at STP (PsTP = 14.7 psi, TSTp = 491.67 °R). When asked to report the flow rate
in SCFH, replace the "ft°/h" unit with "SCFH" (ie., "1 SCFH").
PSTpVscau = iRTSTp → Vaczu = ARTSTP
PSTP
Note that Vscen is different from VSTP. VSTP is always paired with iStp = 1 lb-mol/h in AES units (or Vsrp = 22.4 L
when nSTp = 1 mol in Sl units), whereas Vscru Uses the true or actual molar flow rate n.
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