Mei Lin, an electrical engineering professor sets up the circuit shown in the figure. The reading of the voltmeter is 5.20 V and the reading of the ammeter is 2.60 mA. Assuming the voltmeter and ammeter are both ideal, calculate the following. (v R 3.00 k (a) the value of R (in ka) (b) the emf (in V) of the battery |v (c) the voltage (in V) across the 3.00 ka resistor V
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- What are the expected readings of the following in the figure below? (R = 9.30 N, AV = 6.20 V) A AV 10.0 N + V 5.00 N + R 4.50 V (a) ideal ammeter (Give your answer in mA.) (b) ideal voltmeter (Give your answer in volts.) V (c) What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was to the right? ideal ammeter ideal voltmeter VConsider the circuit shown in the figure below, where R₁ = 8.00, R₂ = 9.00 , and = 7.00 V. 10.0 Ω 2.00 Ω 5.00 Ω www E R₁ www (a) Find the voltage (in V) across R₁. V R₂ www (b) Find the current (in A) in R₁. A (i)In the circuit in the figure below, the emf equals 5.78 V and has negligible internal resistance. The capacitance equals 1.45 µF and the resistance equals 1.95 MN. Switch S has been closed for a long time. Switch S is opened. After a time interval equal to one time constant of the circuit has elapsed, find the following. (a) the charge on the capacitor plate on the right (b) the rate at which the charge is increasing µC/s (c) the current µC/s (d) the power supplied by the battery (e) the power delivered to the resistor (f) the rate at which the energy stored in the capacitor is increasing pw R
- Two identical resistors of R0 = 71 Ω are connected head-to-tail. (a) Express the resistance R0 of one of the resistors in terms of the resistivity ρ, length L, and the cross section area A. (b) Calculate the total resistance R of the two resistors in ohms.Gloria, a lab technician for an electronics company sets up the circuit shown in the figure. The reading of the voltmeter is 5.20 V and the reading of the ammeter is 3.10 mA. Assuming the voltmeter and ammeter are both ideal, calculate the following.(a)the value of R (in kΩ) (b)the emf (in V) of the battery (c)the voltage (in V) across the 3.00 kΩ resistor VAn engineer built the circuit depicted in the figure. Assuming E = 8.40 V and R = 5.80 N, find the following quantities. 12.0 V 4.00 N 2.00 N R (a) the current in the 2.00 O resistor (Enter the magnitude in mA.) (b) the potential difference (in V) between points a and b Vo - Va = V
- An ammeter with resistance 'RA' is connected in series with resistance R=100 ohms. The applied voltage V= 200V. Determine the error (E) & percentage error (%E) in the current measurement due to loading effect of ammeter when- (i) RA =0.2(Ohms) (ii) RA = 20.0 (Ohms).Given that E= 12.0 V, R₁ = 1.00 S2, R₂ = 2.00 S2, R3 = 3.00 S2, and R4 = 4.00 2, calculate the following: (a) the equivalent resistance of the circuit, (b) the power supplied to the circuit by the EMF, (c) the voltage across R3 and (d) the current through R4. Include the reduced circuit diagrams for this situation. R₁ E ww/h www www R₂ RA Rg: wwwWhat are the expected readings of the following in the figure below? (R = 7.60 Q, AV = 6.40 V) A R 10.0 Ω AV + w V w 5.00 Ω + R 4.50 V w (a) ideal ammeter (Give your answer in mA.) mA (b) ideal voltmeter (Give your answer in volts.) V i (c) What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was to the right? ideal ammeter ideal voltmeter mA V
- What are the expected readings of the following in the figure below? (R = 9.50 Q, AV = 6.50 V) A AV 10.0 N 5.00 N + R 4.50 V (a) ideal ammeter (Give your answer in mA.) (b) ideal voltmeter (Give your answer in volts.) V (c) What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was to the right? ideal ammeter ideal voltmeter V4.1Consider the circuit shown in the figure below. (Assume R = 4.80 Ω and ΔV = 12.0 V.) (a) Find the equivalent resistance of the circuit in the figure. I FOUND IT TO BE 12.11 OHMS(b) Find each current in the circuit.(c) Find the potential difference across each resistor.(d) Find the power dissipated by each resistor.