Medical insurance status-covered (C) or not covered (N)-is determined for each individual arriving for treatment at a hospital's emergency room. Consider the chance experiment in which thisdetermination is made for two randomly selected patients.The simple events are o, = (C, C), meaning that the first patient selected was covered and the second patient selected was also covered, o, = (C, N), 0, = (N, C), and O4 = (N, N). Suppose thatprobabilities are P(0,) = 0.81, P(O,) = 0.09, P(0,) = 0.09, and P(0,) = 0.01.(a) What simple events are contained in A, the event that at most one patient is not covered?O A = {(C, C), (C, N), (N, N)}O A = {(C, C), (N, C), (N, N)}O A = {(C, N), (N, C)}O A = {(C, N), (N, C), (N, N)}O A = {(C, C), (C, N), (N, C)}Calculate P(A).P(A) =(b) What simple events are contained in B, the event that the two patients have different statuses with respect to coverage?O B = {(C, C), (C, N)}O B = {(C, C), (N, N)}O B = {(C, N), (N, C)}O B = {(C, N), (N, N)}O the empty setCalculate P(B).P(B) =

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Medical insurance status-covered (C) or not covered ()-is determined for each individual arriving for treatment at a hospital's emergency room. Consider the chance experiment in which this determination is made for two randomly selected patients. The simple events are o, = (C, C), meaning that the first patient selected was covered and the second patient selected was also covered, 0, = (C, N), 03 = (N, C), and O, = (N, N). Suppose that probabilities are P(0,) = 0.81, P(O,) = 0.09, P(0,) = 0.09, and P(0,) = 0.01. (a) What simple events are contained in A, the event that at most one patient is not covered? O A = {(C, C), (C, N), (N, N)} O A = {(C, C), (N, C), (N, N)} O A = {(C, N), (N, C)} O A = {(C, N), (N, C), (N, N)} O A = {(C, C), (C, N), (N, C)} Calculate P(A). P(A) = (b) What simple events are contained in B, the event that the two patients have different statuses with respect to coverage? O B = {(C, C), (C, N)} O B = {(C, C), (N, N)} O B = {(C, N), (N, C)} O B = {(C, N), (N, N)} O the empty set Calculate P(B). P(B) =

Medical insurance status-covered (C) or not covered ()-is determined for each individual arriving for treatment at a hospital's emergency room. Consider the chance experiment in which this determination is made for two randomly selected patients. The simple events are o, = (C, C), meaning that the first patient selected was covered and the second patient selected was also covered, 0, = (C, N), 03 = (N, C), and O, = (N, N). Suppose that probabilities are P(0,) = 0.81, P(O,) = 0.09, P(0,) = 0.09, and P(0,) = 0.01. (a) What simple events are contained in A, the event that at most one patient is not covered? O A = {(C, C), (C, N), (N, N)} O A = {(C, C), (N, C), (N, N)} O A = {(C, N), (N, C)} O A = {(C, N), (N, C), (N, N)} O A = {(C, C), (C, N), (N, C)} Calculate P(A). P(A) = (b) What simple events are contained in B, the event that the two patients have different statuses with respect to coverage? O B = {(C, C), (C, N)} O B = {(C, C), (N, N)} O B = {(C, N), (N, C)} O B = {(C, N), (N, N)} O the empty set Calculate P(B). P(B) =

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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