Mechanism 4: Bromination is a multi-step process. In this mechanism, the pi bond attacks the bromine molecule as in Mechanism 1. Some time after the carbocation is formed, the bromine atom donates a pair of electrons to form the bromonium ion. This step is slow because a strained 3-member ring is formed, and this gives time for bond rotation around the C-C bond before forming the 3-member ring, as shown. This means that two different bromonium ions are formed, leading to a mixture of products-both the meso compound and the pair of enantiomers will be formed. Br-Br OBr Br Br H Ph Ph slow Ph fast (meso) H. Br H H. Ph Ph Ph e H. H. С-С bond rotation Ph Br Br Br OBr Ph (racemic) Ph Ph slow Phy. Ph fast H H. H H H. Br H.

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Which isomer(s) of stilbene dibromide would be formed if the reaction followed Mechanism 4? 

**Mechanism 4: Bromination is a multi-step process. In this mechanism, the pi bond attacks the bromine molecule as in Mechanism 1. Some time after the carbocation is formed, the bromine atom donates a pair of electrons to form the bromonium ion. This step is slow because a strained 3-member ring is formed, and this gives time for bond rotation around the C—C bond before forming the 3-member ring, as shown. This means that two different bromonium ions are formed, leading to a mixture of products—both the meso compound and the pair of enantiomers will be formed.**

**Diagram Explanation:**

- The diagram outlines the bromination mechanism: 
  - Initially, the pi bond of a molecule with phenyl groups (Ph) attacks a bromine molecule (Br—Br), forming a carbocation.
  - The bromine then donates electrons to form a bromonium ion in a slow step that produces a strained 3-member ring.
  - Bond rotation around the C—C bond allows for two different formations of the bromonium ion.
  - In one path, rapid formation leads to a meso compound, characterized by a symmetrical distribution of bromine and hydrogen atoms.
  - In the alternate path, rapid formation results in a pair of enantiomers, producing a racemic mixture with an asymmetric distribution of bromine and hydrogen atoms.
Transcribed Image Text:**Mechanism 4: Bromination is a multi-step process. In this mechanism, the pi bond attacks the bromine molecule as in Mechanism 1. Some time after the carbocation is formed, the bromine atom donates a pair of electrons to form the bromonium ion. This step is slow because a strained 3-member ring is formed, and this gives time for bond rotation around the C—C bond before forming the 3-member ring, as shown. This means that two different bromonium ions are formed, leading to a mixture of products—both the meso compound and the pair of enantiomers will be formed.** **Diagram Explanation:** - The diagram outlines the bromination mechanism: - Initially, the pi bond of a molecule with phenyl groups (Ph) attacks a bromine molecule (Br—Br), forming a carbocation. - The bromine then donates electrons to form a bromonium ion in a slow step that produces a strained 3-member ring. - Bond rotation around the C—C bond allows for two different formations of the bromonium ion. - In one path, rapid formation leads to a meso compound, characterized by a symmetrical distribution of bromine and hydrogen atoms. - In the alternate path, rapid formation results in a pair of enantiomers, producing a racemic mixture with an asymmetric distribution of bromine and hydrogen atoms.
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