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**Pregunta 1 sobre el Mecanismo** Para el mecanismo de la figura, en el instante que se muestra, \(O_1\) es el centro de curvatura del eslabón ranurado 6 (segmento circular). Dado: - \(\omega_2 = 10 \, \text{rad/s sentido horario}\) - \(\alpha_2 = 23 \, \text{rad/s}^2 \text{ sentido antihorario}\) - \(\theta_2 = 44^\circ\) - \(\beta = 52^\circ\) - \(O_1O_6 = 115 \, \text{cm}\) - \(O_1O_4 = 39 \, \text{cm}\) - \(O_2O_4 = 30 \, \text{cm}\) - \(O_2A = 15 \, \text{cm}\) - \(O_4B = 78 \, \text{cm}\) **Calcular: \(\omega_3, \alpha_3, \omega_6\) y \(\alpha_6\)** **NOTA:** Respetar la numeración de los eslabones. Enviar el archivo de respaldo de cálculos remarcando las respuestas, sin esto no se calificará. In the diagram, there is a curved slotted link labeled as “6,” with points \(O_1, O_2,\) and \(O_4\) marked along its path. The angular velocities and accelerations (\(\omega\) and \(\alpha\)), as well as specific angular directions and segment dimensions, are provided. The challenge is to calculate the angular speeds and accelerations of the other components of the mechanism (\(\omega_3, \alpha_3, \omega_6,\) and \(\alpha_6\)), taking into account the established angular and linear relationships between the parts. Additionally, angles \(\theta_2\) and \(\beta\) are defined, which will likely influence the solution calculations. The segments between different points have specific lengths which will be crucial for determining velocity and acceleration using kinematic equations. The diagram includes various labeled points and links that indicate a typical mechanical linkage system. The curved path of link “6” suggests it follows an arc around \(O_1\), emphasizing the relevance of

**Pregunta 1 sobre el Mecanismo** Para el mecanismo de la figura, en el instante que se muestra, \(O_1\) es el centro de curvatura del eslabón ranurado 6 (segmento circular). Dado: - \(\omega_2 = 10 \, \text{rad/s sentido horario}\) - \(\alpha_2 = 23 \, \text{rad/s}^2 \text{ sentido antihorario}\) - \(\theta_2 = 44^\circ\) - \(\beta = 52^\circ\) - \(O_1O_6 = 115 \, \text{cm}\) - \(O_1O_4 = 39 \, \text{cm}\) - \(O_2O_4 = 30 \, \text{cm}\) - \(O_2A = 15 \, \text{cm}\) - \(O_4B = 78 \, \text{cm}\) **Calcular: \(\omega_3, \alpha_3, \omega_6\) y \(\alpha_6\)** **NOTA:** Respetar la numeración de los eslabones. Enviar el archivo de respaldo de cálculos remarcando las respuestas, sin esto no se calificará. In the diagram, there is a curved slotted link labeled as “6,” with points \(O_1, O_2,\) and \(O_4\) marked along its path. The angular velocities and accelerations (\(\omega\) and \(\alpha\)), as well as specific angular directions and segment dimensions, are provided. The challenge is to calculate the angular speeds and accelerations of the other components of the mechanism (\(\omega_3, \alpha_3, \omega_6,\) and \(\alpha_6\)), taking into account the established angular and linear relationships between the parts. Additionally, angles \(\theta_2\) and \(\beta\) are defined, which will likely influence the solution calculations. The segments between different points have specific lengths which will be crucial for determining velocity and acceleration using kinematic equations. The diagram includes various labeled points and links that indicate a typical mechanical linkage system. The curved path of link “6” suggests it follows an arc around \(O_1\), emphasizing the relevance of

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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For the mechanism of the figure at the instant shown O1 is the center of curvature of the slotted link 6 (circular serment).

W2= 10rad/s clockwise

α2= 23rad/s2 counter-clock wise

θ2= 44°

β=52°

O1O6=115cm

O1O4=39cm

O1O4=30cm

O2A= 15cm

O4B= 78cm

calculate:

ω4 [rad/s] = ?

α4 [rad/s2]= ?

ω6 [rad/s] = ?

α6 [rad/s2]= ?

**Pregunta 1 sobre el Mecanismo** Para el mecanismo de la figura, en el instante que se muestra, \(O_1\) es el centro de curvatura del eslabón ranurado 6 (segmento circular). Dado: - \(\omega_2 = 10 \, \text{rad/s sentido horario}\) - \(\alpha_2 = 23 \, \text{rad/s}^2 \text{ sentido antihorario}\) - \(\theta_2 = 44^\circ\) - \(\beta = 52^\circ\) - \(O_1O_6 = 115 \, \text{cm}\) - \(O_1O_4 = 39 \, \text{cm}\) - \(O_2O_4 = 30 \, \text{cm}\) - \(O_2A = 15 \, \text{cm}\) - \(O_4B = 78 \, \text{cm}\) **Calcular: \(\omega_3, \alpha_3, \omega_6\) y \(\alpha_6\)** **NOTA:** Respetar la numeración de los eslabones. Enviar el archivo de respaldo de cálculos remarcando las respuestas, sin esto no se calificará. In the diagram, there is a curved slotted link labeled as “6,” with points \(O_1, O_2,\) and \(O_4\) marked along its path. The angular velocities and accelerations (\(\omega\) and \(\alpha\)), as well as specific angular directions and segment dimensions, are provided. The challenge is to calculate the angular speeds and accelerations of the other components of the mechanism (\(\omega_3, \alpha_3, \omega_6,\) and \(\alpha_6\)), taking into account the established angular and linear relationships between the parts. Additionally, angles \(\theta_2\) and \(\beta\) are defined, which will likely influence the solution calculations. The segments between different points have specific lengths which will be crucial for determining velocity and acceleration using kinematic equations. The diagram includes various labeled points and links that indicate a typical mechanical linkage system. The curved path of link “6” suggests it follows an arc around \(O_1\), emphasizing the relevance of
Transcribed Image Text:**Pregunta 1 sobre el Mecanismo** Para el mecanismo de la figura, en el instante que se muestra, \(O_1\) es el centro de curvatura del eslabón ranurado 6 (segmento circular). Dado: - \(\omega_2 = 10 \, \text{rad/s sentido horario}\) - \(\alpha_2 = 23 \, \text{rad/s}^2 \text{ sentido antihorario}\) - \(\theta_2 = 44^\circ\) - \(\beta = 52^\circ\) - \(O_1O_6 = 115 \, \text{cm}\) - \(O_1O_4 = 39 \, \text{cm}\) - \(O_2O_4 = 30 \, \text{cm}\) - \(O_2A = 15 \, \text{cm}\) - \(O_4B = 78 \, \text{cm}\) **Calcular: \(\omega_3, \alpha_3, \omega_6\) y \(\alpha_6\)** **NOTA:** Respetar la numeración de los eslabones. Enviar el archivo de respaldo de cálculos remarcando las respuestas, sin esto no se calificará. In the diagram, there is a curved slotted link labeled as “6,” with points \(O_1, O_2,\) and \(O_4\) marked along its path. The angular velocities and accelerations (\(\omega\) and \(\alpha\)), as well as specific angular directions and segment dimensions, are provided. The challenge is to calculate the angular speeds and accelerations of the other components of the mechanism (\(\omega_3, \alpha_3, \omega_6,\) and \(\alpha_6\)), taking into account the established angular and linear relationships between the parts. Additionally, angles \(\theta_2\) and \(\beta\) are defined, which will likely influence the solution calculations. The segments between different points have specific lengths which will be crucial for determining velocity and acceleration using kinematic equations. The diagram includes various labeled points and links that indicate a typical mechanical linkage system. The curved path of link “6” suggests it follows an arc around \(O_1\), emphasizing the relevance of
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Step 1

Given Data

W2= 10rad/s clockwise

α2= 23rad/s2 counter-clock wise

θ2= 44°

β=52°

O1O6=115cm

O1O4=39cm

O1O4=30cm

O2A= 15cm

O4B= 78cm

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