mec e ⑤ Rated Power, Pm = 2000 W Pinput=? Te = ? W = ? Т ? = Pmec=Tew ⑥Te = Ky. If. Ia Equation ① put and ⑤ together Pmec = (KT. IP. Ia). w Fос equation 2 Iα = V - E √(KE-IF-W) Ra Ra put and ② together Pmec = Ky · If⋅ (V-KG. If⋅ W ) Ra PMRC = KT · IP. (V-Ke-IR) Ra 2000 = (0.3) (1.875). (372.19). (0.3)·(1.875). 2000 W 0.3.1.875.377.19 w2 W 6/8 = 3.09 rad/s

mec e ⑤ Rated Power, Pm = 2000 W Pinput=? Te = ? W = ? Т ? = Pmec=Tew ⑥Te = Ky. If. Ia Equation ① put and ⑤ together Pmec = (KT. IP. Ia). w Fос equation 2 Iα = V - E √(KE-IF-W) Ra Ra put and ② together Pmec = Ky · If⋅ (V-KG. If⋅ W ) Ra PMRC = KT · IP. (V-Ke-IR) Ra 2000 = (0.3) (1.875). (372.19). (0.3)·(1.875). 2000 W 0.3.1.875.377.19 w2 W 6/8 = 3.09 rad/s

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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