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the wave form of V, & iL. D) Sketch For V₁ = [-12 Ve */ 66-67115 y O 55=333.35ms > t(ms) -12 女 JVLMA. For IL : [-400mA (1-e² 66.67ms] 57=333.35ms 40-400 ViL (MA) 1 E(ms) ST 5(66.67ms) b ST = 333,35ms For the following circuit, E 12 V www 10 Ω w 20 Ω Figure 3: LiL + L2H UL

the wave form of V, & iL. D) Sketch For V₁ = [-12 Ve */ 66-67115 y O 55=333.35ms > t(ms) -12 女 JVLMA. For IL : [-400mA (1-e² 66.67ms] 57=333.35ms 40-400 ViL (MA) 1 E(ms) ST 5(66.67ms) b ST = 333,35ms For the following circuit, E 12 V www 10 Ω w 20 Ω Figure 3: LiL + L2H UL

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Can you check if the answser that I did in each question is correct?

(a) Determine τ

τ = 66.67ms


(b) Write the mathematical expression for the voltage VL using the defined
polarities and direction.

VL= -12Ve-t/66.67ms


(c) Write the mathematical expression for the current IL using the defined
polarities and direction.

IL = -400mA(1 - e-t/66.67ms)

(d)  Sketch the waveforms of vL and iL

the wave form of V, & iL. D) Sketch For V₁ = [-12 Ve */ 66-67115 y O 55=333.35ms > t(ms) -12 女 JVLMA. For IL : [-400mA (1-e² 66.67ms] 57=333.35ms 40-400 ViL (MA) 1 E(ms) ST 5(66.67ms) b ST = 333,35ms
Transcribed Image Text:the wave form of V, & iL. D) Sketch For V₁ = [-12 Ve */ 66-67115 y O 55=333.35ms > t(ms) -12 女 JVLMA. For IL : [-400mA (1-e² 66.67ms] 57=333.35ms 40-400 ViL (MA) 1 E(ms) ST 5(66.67ms) b ST = 333,35ms
For the following circuit, E 12 V www 10 Ω w 20 Ω Figure 3: LiL + L2H UL
Transcribed Image Text:For the following circuit, E 12 V www 10 Ω w 20 Ω Figure 3: LiL + L2H UL
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