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(MC) A This is the only question in this section. Question If f (x) = cos x, then the Mean Value Theorem guarantees that somewhere between 0 and π/3, f'(x) = Answer Attempt 1 out of 2 2T 0-1 42 cof70605-47 Reserved. O 0 2 Submit Answer

(MC) A This is the only question in this section. Question If f (x) = cos x, then the Mean Value Theorem guarantees that somewhere between 0 and π/3, f'(x) = Answer Attempt 1 out of 2 2T 0-1 42 cof70605-47 Reserved. O 0 2 Submit Answer

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Mean Value Theorem Question **Context:** This is the only question in this section. **Question:** If \( f(x) = \cos x \), then the Mean Value Theorem guarantees that somewhere between \( 0 \) and \( \pi/3 \), \( f'(x) = \) **Answer Options:** (Attempt 1 out of 2) - \( \frac{-3}{2\pi} \) - \(-1\) - \( \frac{1}{2} \) - \(\frac{\sqrt{3}}{2}\) - \(0\) *Please select the correct answer and then click "Submit Answer."*
Transcribed Image Text:### Mean Value Theorem Question **Context:** This is the only question in this section. **Question:** If \( f(x) = \cos x \), then the Mean Value Theorem guarantees that somewhere between \( 0 \) and \( \pi/3 \), \( f'(x) = \) **Answer Options:** (Attempt 1 out of 2) - \( \frac{-3}{2\pi} \) - \(-1\) - \( \frac{1}{2} \) - \(\frac{\sqrt{3}}{2}\) - \(0\) *Please select the correct answer and then click "Submit Answer."*
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