### Diagram ExplanationThe provided diagram depicts a physical setup consisting of a horizontal bar, a cable, and a hanging store sign. Below is a detailed description of the elements in the diagram:1. **Horizontal Bar**: - Length: \( L = 1.2 \text{ m} \) - Mass: \( m_b = 12 \text{ kg} \) - Uniform density2. **Cable**: - The right end of the horizontal bar is connected to a cable. - The cable forms an angle \( \theta \) of 31° with the horizontal.3. **Hinge**: - The left end of the bar is hinged, allowing it to pivot at this point.4. **Store Sign**: - A store sign with a mass \( m_s = 18 \text{ kg} \) is suspended vertically below the bar. - The sign is located at a distance \( d = 0.18 \text{ m} \) from the right end of the bar.### Problem StatementGiven the setup, the objective is to:**Find the magnitude of the vertical hinge force.**### Understanding the Diagram- A vertical bar is shown on the left, representing a wall to which the horizontal bar is hinged.- The horizontal bar, marked with length \( L \) and mass \( m_b \), extends from the hinge.- A cable is attached to the right end of the horizontal bar and inclined at 31° with respect to the horizontal direction.- The store sign is hanging below the bar, at a specified distance from the right end.### Steps to SolutionTo find the magnitude of the vertical hinge force, follow these steps:1. **Identify Forces Acting on the Bar**: - Weight of the bar (\( W_b \)) acting downward at its center of mass. - Tension in the cable (\( T \)) supporting the bar's right end. - Weight of the store sign (\( W_s \)) acting downward 0.18 m from the right end. - Hinge force containing vertical (\( F_V \)) and horizontal (\( F_H \)) components.2. **Equilibrium Conditions**: The bar is in static equilibrium, so: - Sum of vertical forces must be zero. - Sum of horizontal forces must be zero. - Sum of torques around the

Answered: Image /qna-images/answer/e3fa4d38-ea94-4ad4-a4bc-200f05044685.jpg

mb: L d- ms A horizontal L=1.2 m long mb=12 kg uniform bar is hinged on the left end and pulled at the right end by a cable. The cable makes 31° angle with horizontal. A 18 kg store sign is suspended below the bar at d=0.18 m from the right end. Find the magnitude of vertical hinge force.

mb: L d- ms A horizontal L=1.2 m long mb=12 kg uniform bar is hinged on the left end and pulled at the right end by a cable. The cable makes 31° angle with horizontal. A 18 kg store sign is suspended below the bar at d=0.18 m from the right end. Find the magnitude of vertical hinge force.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: Suppose that P₁ = 600 lb and P₂ = 800 lb. Suggestion: Use the sections shown in (Figure 1). Figure 6…

Q: A metal bar 10 m long and weighs 50 N is supported at the 7 m mark by a fulcrum. A 100 N bag is…

Q: a) The rigid bar ABD is supported by a journal bearing (radial bearing) at A, a vertical rope at B,…

Q: The rectangular bar shown is connected to a support bracket with a 24 mm diameter pin. The width of…

A: Given Data The diameter of pin is:d=24mm=24×10-3 m The width of the rectangular bar is:b=70…

Q: A crane boom 10 m long, weighing 870 N and having its center of gravity 3 m from the bottom, is…

Q: The vertical structure ABCD shown in Figure 1(a) is subjected to a system of coplanar forces and a…

Q: A stepped bar is held in equilibrium by several forces acting at different points along the length,…

Q: A floor hoist supports an engine of weight WE 2.9 kN. As illustrated in the figure below, the floor…

Q: A sandwich board advertising sign is constructed as shown in the figure below. Hinge- 0.50m Chain…

A: Given Data: m=7.2 kg To Find: (a) The tension in the chain. (b) Force exerted by each side on the…

Q: A floor hoist supports an engine of weight WE 2.9 kN. As illustrated in the figure below, the floor…

A: The value are .The weight of the engine is The angle is

Q: 1000 lb 4 ft 4 ft B 5 ft A 3 ftr 10 ft 13 ft 600 lb -9 ft- 5 ft E Show Transcribed Text The frame is…

Q: Problem 4.2 - Bar AB is 4 feet long and weighs 20 lbs. It is supported by two cords and by smooth…

Q: Consider the bracket shown in Fig-3. If: • F1 = 10 lb @ -90° • a = 2 ft • b= 4 ft c= 1 ft then, what…

A: Consider the free body diagram of member AC, Here,

Q: The structure shown in Fig 4-4.17 consists of two simple trusses joined by bars Be, CF and DG. Find…

Q: The mass-less bar (OAB) shown in the figure is supported by a ball and socket support at point O and…

Question

### Diagram Explanation

The provided diagram depicts a physical setup consisting of a horizontal bar, a cable, and a hanging store sign. Below is a detailed description of the elements in the diagram:

1. **Horizontal Bar**:
- Length: \( L = 1.2 \text{ m} \)
- Mass: \( m_b = 12 \text{ kg} \)
- Uniform density

2. **Cable**:
- The right end of the horizontal bar is connected to a cable.
- The cable forms an angle \( \theta \) of 31° with the horizontal.

3. **Hinge**:
- The left end of the bar is hinged, allowing it to pivot at this point.

4. **Store Sign**:
- A store sign with a mass \( m_s = 18 \text{ kg} \) is suspended vertically below the bar.
- The sign is located at a distance \( d = 0.18 \text{ m} \) from the right end of the bar.

### Problem Statement

Given the setup, the objective is to:

**Find the magnitude of the vertical hinge force.**

### Understanding the Diagram

- A vertical bar is shown on the left, representing a wall to which the horizontal bar is hinged.
- The horizontal bar, marked with length \( L \) and mass \( m_b \), extends from the hinge.
- A cable is attached to the right end of the horizontal bar and inclined at 31° with respect to the horizontal direction.
- The store sign is hanging below the bar, at a specified distance from the right end.

### Steps to Solution

To find the magnitude of the vertical hinge force, follow these steps:

1. **Identify Forces Acting on the Bar**:
- Weight of the bar (\( W_b \)) acting downward at its center of mass.
- Tension in the cable (\( T \)) supporting the bar's right end.
- Weight of the store sign (\( W_s \)) acting downward 0.18 m from the right end.
- Hinge force containing vertical (\( F_V \)) and horizontal (\( F_H \)) components.

2. **Equilibrium Conditions**:
The bar is in static equilibrium, so:
- Sum of vertical forces must be zero.
- Sum of horizontal forces must be zero.
- Sum of torques around the

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Please give me the solution in a correct way. Don't use chatgpt
1. Calculate the support reactions, calculate internal forces on the designated section C, and plot the internal force diagrams of the frames shown below. 6m RA 4.I M 湖4.3回 Pa 2ANm y武汉理出版 5 m 4.4图 4.5 4.6图 6 kN D. 3 m 3 m 題4.7图題4.8图 2 KN/
1 m Ql: A: Draw a Free-Body Diagram of the bars AD and BC shown in the figure. Assume all hinges to be smooth and neglect the weight 1 m 500 N of each bars. I m
The prismatic bar AC is supported by a hinge at C and cable ADB that runs through a frictionless pulley at D as shown in the figure. What is the tension in the cable if the bar weighs 5 Ib/ft? D 3 ft 5 ft B 5 ft
The vertical structure ABCD shown in Figure 1(a) is subjected to a (a) system of coplanar forces and a moment. The structure is simply supported at D with a frictionless pin and is roller-supported at A. i. Sketch the free body diagram (FBD). ii. Take moments about D and hence find the reaction force at support A. 35 kNA A5m 05m C. 80 kN+ B. 60 100 kNm 75 KN 2 m 05m 45
The truss shown below has a hinge support at point A, a horizontal roller at point B, and is subjected to two point loads (P1 and P2). If P1- 30 kN and P2 - 55 kN, what is the force, in kN, in member AE? NOTE: Enter a positive value if the member is in Tension and a negative value if the member is in Compression. PI (KN) 60 A 4 m 4 m P2 (kN)
The rigid arm of negligible weight shown in the figure supports a load of F= 819 N. The chains are fixed to the wall at points D and E and the support A is ball-and-socket (spherical). Find the magnitude of the force FBE
A horizontal L=1.2 m long mb=14 kg uniform bar is hinged on the left end and pulled at the right end by a cable. The cable makes 23° angle with horizontal. A 24 kg store sign is suspended below the bar at d=0.18 m from the right end. Find the magnitude of horizontal hinge force.
As per the crane shown in the Figure. Determine the force member at BD.
7. A compound lever as shown below. Find the effort P. if the system is used to lift a mass of 800kg. (10) S00 mam 400 mm 350 mm S0mm 800 kg 8. An oil drum 600mm in diameter and length Im is to be rolled over a step 120mm in height. Find the least pull through the centre of the drum required just to turn the drum over the step. Also find the reaction on the step. Assuming all the surfaces to be smooth. Take density of oil as 1 kg/litre and neglecting weight of the drum. (10) 50 mm
Solve this 2d ridgid body
Calculate the forces arising on A, B and D pins with the effect of 500N horizontal force in the frame system shown in the figure.