maximum allowable chip operating temperature. Consider a 15 mm x 15 mm square chip. In order to improve the heat dissipation, a five by five array of copper pin fins are to be joined to the outer surface of the chip. The fins have a diameter of 1.5 mm and a length of 15 mm. Cooling air can be supplied at T = 25°C, and the maximum allowable chip base temperature is To=75°C. The convective heat transfer coefficient is h = 250 W/m²-K, and the copper has a thermal conductivity of k = 401 W/m•K. %3D Consider two cases: Case A: Convecting Tip, and Case B: Adiabatic Tip And for each calculate the following at steady state: (a) Heat transfer rate from a single fin. (b) Efficiency of a single fin. (c) Total heat transfer rate of the array.
maximum allowable chip operating temperature. Consider a 15 mm x 15 mm square chip. In order to improve the heat dissipation, a five by five array of copper pin fins are to be joined to the outer surface of the chip. The fins have a diameter of 1.5 mm and a length of 15 mm. Cooling air can be supplied at T = 25°C, and the maximum allowable chip base temperature is To=75°C. The convective heat transfer coefficient is h = 250 W/m²-K, and the copper has a thermal conductivity of k = 401 W/m•K. %3D Consider two cases: Case A: Convecting Tip, and Case B: Adiabatic Tip And for each calculate the following at steady state: (a) Heat transfer rate from a single fin. (b) Efficiency of a single fin. (c) Total heat transfer rate of the array.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![**Heat Transfer from Extended Surfaces**
### Introduction
This topic explores the heat transfer from extended surfaces, often referred to as fins. The analysis involves solving differential equations subject to specific boundary conditions.
### General Solution
The temperature distribution along the fin is expressed as:
\[
\theta = c_1 e^{mx} + c_2 e^{-mx}
\]
### Case A: Boundary Conditions – Convection at the Tip
- At \( x = 0 \): \( T = T_0 \)
- At \( x = L \):
\[
-k \left( \frac{dT}{dx} \right)_{x=L} = h(T_L - T_\infty)
\]
### Temperature Profile Solution
The temperature profile along the fin is given by:
\[
\frac{\theta}{\theta_0} = \frac{\cosh[m(L-x)] + \frac{(h/mx)\sinh[m(L-x)]}}{\cosh mL + \frac{(h/mk)\sinh mL}}
\]
(Equation 17-40)
### Heat Transfer Rate
The heat transfer rate from the fin is calculated using:
\[
q = kA m \theta_0 \frac{\sinh mL + (h/mk)\cosh mL}{\cosh mL + (h/mk)\sinh mL}
\]
(Equation 17-46)
### Diagram Description
The diagram includes schematic representations of two different types of extended surfaces or fins illustrating heat flow. The left image shows a cylindrical fin, while the right image displays a rectangular fin.
These equations and concepts are crucial for understanding how fins enhance heat dissipation in various engineering applications.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc2a758a4-69fc-4b07-9ca9-f4af1d363e17%2Fc3e9012e-c88b-4871-8b4e-1fe18a8449e0%2Folc91hh_processed.png&w=3840&q=75)
Transcribed Image Text:**Heat Transfer from Extended Surfaces**
### Introduction
This topic explores the heat transfer from extended surfaces, often referred to as fins. The analysis involves solving differential equations subject to specific boundary conditions.
### General Solution
The temperature distribution along the fin is expressed as:
\[
\theta = c_1 e^{mx} + c_2 e^{-mx}
\]
### Case A: Boundary Conditions – Convection at the Tip
- At \( x = 0 \): \( T = T_0 \)
- At \( x = L \):
\[
-k \left( \frac{dT}{dx} \right)_{x=L} = h(T_L - T_\infty)
\]
### Temperature Profile Solution
The temperature profile along the fin is given by:
\[
\frac{\theta}{\theta_0} = \frac{\cosh[m(L-x)] + \frac{(h/mx)\sinh[m(L-x)]}}{\cosh mL + \frac{(h/mk)\sinh mL}}
\]
(Equation 17-40)
### Heat Transfer Rate
The heat transfer rate from the fin is calculated using:
\[
q = kA m \theta_0 \frac{\sinh mL + (h/mk)\cosh mL}{\cosh mL + (h/mk)\sinh mL}
\]
(Equation 17-46)
### Diagram Description
The diagram includes schematic representations of two different types of extended surfaces or fins illustrating heat flow. The left image shows a cylindrical fin, while the right image displays a rectangular fin.
These equations and concepts are crucial for understanding how fins enhance heat dissipation in various engineering applications.

Transcribed Image Text:1. As more and more components are placed on a single integrated circuit (chip), the amount of heat that is dissipated continues to increase. However, this increase is limited by the maximum allowable chip operating temperature. Consider a 15 mm x 15 mm square chip. In order to improve the heat dissipation, a five by five array of copper pin fins are to be joined to the outer surface of the chip. The fins have a diameter of 1.5 mm and a length of 15 mm. Cooling air can be supplied at T∞ = 25°C, and the maximum allowable chip base temperature is T₀ = 75°C. The convective heat transfer coefficient is h = 250 W/m²·K, and the copper has a thermal conductivity of k = 401 W/m·K.
Consider two cases: Case A: Convecting Tip, and Case B: Adiabatic Tip
And for each calculate the following at steady state:
(a) Heat transfer rate from a single fin.
(b) Efficiency of a single fin.
(c) Total heat transfer rate of the array.
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