Max average daily flow = 16 MGD Minimum depths 10’ for primary clarifier and 15’ for secondary clarifier Find: Dimensions of clarifiers (Hint: Consider service loading and detention time) Determine Volume by finding detention time (Assume 90 minutes = 0.0625 Days) 0.0625 Days = V / 16 MGD therefore, Volume = 1,000,000 Gallons = 133,681 ft^3 Primary Clarifier (10’ depth): Cross sectional area = 13,368.1 ft^2 =0.25*pi*d^2
Max average daily flow = 16 MGD Minimum depths 10’ for primary clarifier and 15’ for secondary clarifier Find: Dimensions of clarifiers (Hint: Consider service loading and detention time) Determine Volume by finding detention time (Assume 90 minutes = 0.0625 Days) 0.0625 Days = V / 16 MGD therefore, Volume = 1,000,000 Gallons = 133,681 ft^3 Primary Clarifier (10’ depth): Cross sectional area = 13,368.1 ft^2 =0.25*pi*d^2
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Max average daily flow = 16 MGD Minimum depths 10’ for primary clarifier and 15’ for secondary clarifier
Find: Dimensions of clarifiers (Hint: Consider service loading and detention time)
Determine Volume by finding detention time (Assume 90 minutes = 0.0625 Days)
0.0625 Days = V / 16 MGD therefore, Volume = 1,000,000 Gallons = 133,681 ft^3
Primary Clarifier (10’ depth): Cross sectional area = 13,368.1 ft^2 =0.25*pi*d^2
therefore, d = 131 ft. = 135 ft.
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