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Match the following functions with their recursive definitions. > n! n(n+1)(2n+1) 6 2n n² 1. f(0) = 1, f(n) = n × f(n − 1) - 2. f(1) = 1, f(n) = f(n − 1) + 2n – 1 3. f(0) = 1, f(n) = 2 × f(n − 1) - 4. f(1) = 1, f(n) = f(n-1) + n²

Match the following functions with their recursive definitions. > n! n(n+1)(2n+1) 6 2n n² 1. f(0) = 1, f(n) = n × f(n − 1) - 2. f(1) = 1, f(n) = f(n − 1) + 2n – 1 3. f(0) = 1, f(n) = 2 × f(n − 1) - 4. f(1) = 1, f(n) = f(n-1) + n²

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Match the following functions with their recursive definitions.** 1. \( n! \) (Factorial): - \( f(0) = 1, \ f(n) = n \times f(n-1) \) 2. \(\frac{n(n+1)(2n+1)}{6}\) (Sum of Squares): - \( f(1) = 1, \ f(n) = f(n-1) + 2n - 1 \) 3. \( 2^n \) (Exponential Function): - \( f(0) = 1, \ f(n) = 2 \times f(n-1) \) 4. \( n^2 \) (Square of a Number): - \( f(1) = 1, \ f(n) = f(n-1) + n^2 \)
Transcribed Image Text:**Match the following functions with their recursive definitions.** 1. \( n! \) (Factorial): - \( f(0) = 1, \ f(n) = n \times f(n-1) \) 2. \(\frac{n(n+1)(2n+1)}{6}\) (Sum of Squares): - \( f(1) = 1, \ f(n) = f(n-1) + 2n - 1 \) 3. \( 2^n \) (Exponential Function): - \( f(0) = 1, \ f(n) = 2 \times f(n-1) \) 4. \( n^2 \) (Square of a Number): - \( f(1) = 1, \ f(n) = f(n-1) + n^2 \)
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