2. Suppose that f(x) = ((.x² + x·5).5 +.r.5).5 when x ≥ 0. Find df(x)/dx. •5 (@ï¥2³ )² +x²)+ [.5(8°.³})^(2x+x^²) ++2^² 6 df = 5 dze

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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can you please simply explain how they got the image on the answer and why the exponent is -1/2 instead of just postive 1/2?

2. Suppose that f(x) = ((.x² + x·5).5 + x-5).5 when x ≥ 0. Find df(x)/dx.
2
(Qxe4x³² )² +ײ¹)³²¹ [·5 (2²+x²) *(2x+x^²)
+x
Q.
(6)
df = 15
5
dre
+ 4x^])
-IN
Transcribed Image Text:2. Suppose that f(x) = ((.x² + x·5).5 + x-5).5 when x ≥ 0. Find df(x)/dx. 2 (Qxe4x³² )² +ײ¹)³²¹ [·5 (2²+x²) *(2x+x^²) +x Q. (6) df = 15 5 dre + 4x^]) -IN
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