Match the following aqueous solutions with the appropriate letter from the column on the right. A. Lowest freezing point 1.0.12 m AlBr3 2.0.18 m FeCl₂ B. Second lowest freezing point C. Third lowest freezing point 3.0.17 m Co(CH3COO)2 4.0.58 m Urea(nonelectrolyte) D. Highest freezing point Submit Answer Retry Entire Group for this question. 9 more group attempts remaining

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Match the following aqueous solutions with the appropriate letter from the column on the right.
1.0.12 m AlBr3
A. Lowest freezing point
2.0.18 m FeCl₂
B. Second lowest freezing point
C. Third lowest freezing point
3.0.17 m Co(CH3COO)2
4.0.58 m Urea(nonelectrolyte)
D. Highest freezing point
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Transcribed Image Text:isited Match the following aqueous solutions with the appropriate letter from the column on the right. 1.0.12 m AlBr3 A. Lowest freezing point 2.0.18 m FeCl₂ B. Second lowest freezing point C. Third lowest freezing point 3.0.17 m Co(CH3COO)2 4.0.58 m Urea(nonelectrolyte) D. Highest freezing point Submit Answer Retry Entire Group for this question. 9 more group attempts remaining Previous Nex> Save and Exit
Expert Solution
Step 1

Depression in freezing point is a colligative property which means that it depends only on the number of particles and not on the nature of the particles.

We know that

∆Tf= i × kf ×m

Where ∆T= depression in freezing point

∆Tf= Ti-Tf

Ti= freezing point of pure solvent

Tf= freezing point of solution

i = vant Hoff factor

Kf= freezing point depression constant

m = molality

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