**Instructions:**Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P = 0.0629 and P = 0.2891.**Details of the Graphs:**1. **Graph (a):** - **Label:** z = 1.06 - **Description:** The graph is a standard normal distribution curve with shading in the tails on both sides, indicating areas of statistical significance. 2. **Graph (b):** - **Label:** z = 1.86 - **Description:** Another standard normal distribution curve with a smaller section shaded in the tails on both sides, reflecting a different P-value.**Task:**Fill in the blanks below to complete the statement:Graph [dropdown menu] displays the area for P = 0.0629 and graph [dropdown menu] displays the area for P = 0.2891 because the P-value [dropdown menu] the [dropdown menu].

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Description: **Instructions:**Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P = 0.0629 and P = 0.2891.**Details of the Graphs:**1. **Graph (a):** - **Label:** z = 1.06 - **Description:**

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Math

Advanced Math

Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P = 0.0629 and P= 0.2891. (a) z=1.06 (b) z= 1.86 Graph V displays the area for P = 0.0629 and graph displays the area for P = 0.2891 because the P-value V the

Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P = 0.0629 and P= 0.2891. (a) z=1.06 (b) z= 1.86 Graph V displays the area for P = 0.0629 and graph displays the area for P = 0.2891 because the P-value V the

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Topic Video

Question

**Instructions:**

Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P = 0.0629 and P = 0.2891.

**Details of the Graphs:**

1. **Graph (a):**
- **Label:** z = 1.06
- **Description:** The graph is a standard normal distribution curve with shading in the tails on both sides, indicating areas of statistical significance.

2. **Graph (b):**
- **Label:** z = 1.86
- **Description:** Another standard normal distribution curve with a smaller section shaded in the tails on both sides, reflecting a different P-value.

**Task:**

Fill in the blanks below to complete the statement:

Graph [dropdown menu] displays the area for P = 0.0629 and graph [dropdown menu] displays the area for P = 0.2891 because the P-value [dropdown menu] the [dropdown menu].

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