Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P 0.0688 and P = 0.3576. (a) z = 0.92 (b) z = 1.82 -z Graph V displays the area for P = 0.0688 and graph v displays the area for P = 0.3576 because the P-value the
Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P 0.0688 and P = 0.3576. (a) z = 0.92 (b) z = 1.82 -z Graph V displays the area for P = 0.0688 and graph v displays the area for P = 0.3576 because the P-value the
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:The image presents two graphs illustrating normal distribution curves with shaded areas corresponding to P-values.
1. **Graph (a)** displays a normal distribution curve with a z-score of 0.92. The shaded area encompasses the central part around the mean, leaving out the tails.
2. **Graph (b)** displays another normal distribution curve, this time with a z-score of 1.82. The shaded area is more concentrated around the mean than in graph (a).
The task is to match each P-value with the graph that displays its area without performing any calculations. The provided P-values are 0.0688 and 0.3576.
**Task Explanation:**
- Users must identify which graph corresponds to each P-value by considering the size of the shaded areas.
- Typically, a lower P-value indicates a smaller shaded region (more extreme), whereas a higher P-value covers a broader area under the curve.
**Completion Instructions:**
- Users must select which graph (a or b) corresponds to P = 0.0688 and which corresponds to P = 0.3576.
- Additionally, explain why the P-value is associated with either a smaller or larger area under the curve based on its extremeness.
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