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Match each equation to the conic section it creates. (x+5)² 25 a. + (y-2)² 4 b. 3x³ + 4y = 25 d. = 1 c. (x + 5)² + (y + 2)² = 98 (y+3)² (x-2)² 21 4 = 1 |e. (y + 5)² = 21 (x − 2) - f. (x + 2)2-(y + 1)² = 9 |g. (x − 5)² = 4(y + 2)² [ [ [ [= [S [S (S

Match each equation to the conic section it creates. (x+5)² 25 a. + (y-2)² 4 b. 3x³ + 4y = 25 d. = 1 c. (x + 5)² + (y + 2)² = 98 (y+3)² (x-2)² 21 4 = 1 |e. (y + 5)² = 21 (x − 2) - f. (x + 2)2-(y + 1)² = 9 |g. (x − 5)² = 4(y + 2)² [ [ [ [= [S [S (S

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Match each equation to the conic section it creates. (x+5)² 25 a. + (y-2)² 4 b. 3x³ + 4y = 25 d. 1 c. (x + 5)² + (y + 2)² = 98 (y+3)² (x-2)² 21 4 = 1 e. (y + 5)² = 21 (x − 2) 1 f. (x + 2)² − (y + 1)² = 9 - |g. (x − 5)² = 4(y + 2)² [Select] [Select] [ Select] [ Select] [Select] [Select] [Select]
Transcribed Image Text:Match each equation to the conic section it creates. (x+5)² 25 a. + (y-2)² 4 b. 3x³ + 4y = 25 d. 1 c. (x + 5)² + (y + 2)² = 98 (y+3)² (x-2)² 21 4 = 1 e. (y + 5)² = 21 (x − 2) 1 f. (x + 2)² − (y + 1)² = 9 - |g. (x − 5)² = 4(y + 2)² [Select] [Select] [ Select] [ Select] [Select] [Select] [Select]
Expert Solution
Step 1

a.

The standard equation of a ellipse is (x+x0)2a2+(y+y0)2b2=1.So (x+5)225+(y-2)24=1  is equation of a ellipse.

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