Mass of unknown ammonium salt Molarity of NaOH(aq), M2 Molarity of HCl(aq), M1 Volume of NaOH(aq) measured For back-titration Initial Volume of HCl(aq) used Final Volume of HCl(aq) used Volume of HCl(aq) used, V1 End Point (Color Change) 0.400g 0.1938 M 0.1942 M 50.00mL OmL 0.415. g 0.1938 M 0.1942 M 50.00mL 23.00mL 42.80mL 50.00ml 23.00mL 50.00mL blue green Yellow 0.403g 0.1938 M 0.1942 M 50.00ML OmL 20.80mL 50.00 mL

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Data Table for Unknown #
8
1 Mass of unknown ammonium salt
2 Molarity of NaOH(aq), M2
3 Molarity of HCl(aq), M1
4 Volume of NaOH(aq) measured
For back-titration
5 Initial Volume of HCl(aq) used
Final Volume of HCl(aq) used
6
7
Volume of HCl(aq) used, V1
End Point (Color Change)
8
Trial 1
0.400q
0.1938 M
0.1942 M
50.00mL
OmL
Trial 2
0.415a
0.1938 M
0.1942 M
50.00mL
23.00mL
42.80mL
50.00ml
23.00mL
50.00mL
blue green → Yellow
Trial 3
0.403g
0.1938 M
0.1942 M
50.00mL
OmL
20.80mL
50.00mL
Transcribed Image Text:Data Table for Unknown # 8 1 Mass of unknown ammonium salt 2 Molarity of NaOH(aq), M2 3 Molarity of HCl(aq), M1 4 Volume of NaOH(aq) measured For back-titration 5 Initial Volume of HCl(aq) used Final Volume of HCl(aq) used 6 7 Volume of HCl(aq) used, V1 End Point (Color Change) 8 Trial 1 0.400q 0.1938 M 0.1942 M 50.00mL OmL Trial 2 0.415a 0.1938 M 0.1942 M 50.00mL 23.00mL 42.80mL 50.00ml 23.00mL 50.00mL blue green → Yellow Trial 3 0.403g 0.1938 M 0.1942 M 50.00mL OmL 20.80mL 50.00mL
Calculations*
A
B
1
2
3
4
NH4+(aq) + OH-(aq) = NH3(aq) + H2O(1)
From back titration of NaOH(aq) with HCl(aq)
M1V1=M2V2
Find V2, the volume of left-over NaOH(aq)
From equation 1
Find the volume (V3) of NaOH(aq) reacted (used) in equation 1
V3 = volume measured - volume left-over
V350.00 mL - V2
6
Find the moles of NaOH(aq) used in equation 1
M = mol/L
mol = ML
mol = MV3
At neutralization (assuming #eq = 1)
mol NH4+ salt(aq) = mol NaOH(aq)
Find the molar mass of ammonium salt
mol = mass
equation 1
molar mass
(make sure V3 is the volume in L)
5
If the calculated mm (from step 4 above) matches the mm given in the Table, #eq = 1,
eq mass is same as the calculated mm.
If the calculated mm matches the eq mass and not the mm, #eq = 2
molar mass = 2 * eq mass
Q Test: Chem 1A lab manual
Transcribed Image Text:Calculations* A B 1 2 3 4 NH4+(aq) + OH-(aq) = NH3(aq) + H2O(1) From back titration of NaOH(aq) with HCl(aq) M1V1=M2V2 Find V2, the volume of left-over NaOH(aq) From equation 1 Find the volume (V3) of NaOH(aq) reacted (used) in equation 1 V3 = volume measured - volume left-over V350.00 mL - V2 6 Find the moles of NaOH(aq) used in equation 1 M = mol/L mol = ML mol = MV3 At neutralization (assuming #eq = 1) mol NH4+ salt(aq) = mol NaOH(aq) Find the molar mass of ammonium salt mol = mass equation 1 molar mass (make sure V3 is the volume in L) 5 If the calculated mm (from step 4 above) matches the mm given in the Table, #eq = 1, eq mass is same as the calculated mm. If the calculated mm matches the eq mass and not the mm, #eq = 2 molar mass = 2 * eq mass Q Test: Chem 1A lab manual
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