Mass of oxygen = 0.49g- 0.33g = 0.16g Number of moles = given mass / molar mass Number of moles of oxygen = 0.16/ 16  = 0.01 mol Molar Mass of magnesium = 24.3g Moles of magnesium = 0.33g / 24.3g = 0.0135 mol   Moles of magnesium 0.0135 1.35 3 4 ------------------------      = _____________  =  ____________ x       ________ = ___ Moles of oxygen 0.01 1 3   3 The ratio between the moles of magnesium used and the moles of oxygen uses is 4/3. Based on your experimental data, write the empirical formula for magnesium oxide. Is this the molecular formula or the simplest formula? Explain how you know this.

Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter4: Stoichiometry Of Chemical Reactions
Section: Chapter Questions
Problem 85E: A 0.025-g sample of a compound composed of boron and hydrogen, with a molecular mass of ~28 amu,...
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Mass of oxygen = 0.49g- 0.33g
= 0.16g

Number of moles = given mass / molar mass

Number of moles of oxygen = 0.16/ 16  = 0.01 mol

Molar Mass of magnesium = 24.3g

Moles of magnesium = 0.33g / 24.3g = 0.0135 mol

  Moles of magnesium 0.0135 1.35 3 4
------------------------      = _____________  =  ____________ x       ________ = ___
Moles of oxygen 0.01 1 3   3

The ratio between the moles of magnesium used and the moles of oxygen uses is 4/3.

Based on your experimental data, write the empirical formula for magnesium oxide.

Is this the molecular formula or the simplest formula? Explain how you know this.



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