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Mass of DRY Filter Paper and Precipitate (day 2) Mass of Calcium Carbonate (Precipitate, day 2) Percent Yield Calculations 1.179 1.179

Mass of DRY Filter Paper and Precipitate (day 2) Mass of Calcium Carbonate (Precipitate, day 2) Percent Yield Calculations 1.179 1.179

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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also D O Chem 105 Online recrystallize-which would add an additional mass on the filter paper when dried. that all the spectator ions are rinsed off the filter paper and precipitate and not /7. Carefully remove the filter paper (it will still be very moist) and place it on a paper towel to dry overnight. A sunny window is a happy medium for wet filter paper as well. 8. Repeat the process one more time for a second trial. This time you will measure 10.0mL of 0.750M Na₂CO3 and 50.0mL of 0.250M CaCl₂ into a new plastic cup.. Don't forget your documentation! Data Table If you are cramped for time, an oven will work set at 200-225°F. Set the wet filter paper on a baking sheet and place in the oven. Check it regularly to not burn the filter paper. Data Entry Quantities Used Theoretical Yield of Precipitate (record here, show calculations below table) Mass of Filter Paper BEFORE experiment Mass of DRY Filter Paper and Precipitate (day 2) Mass of Calcium Carbonate (Precipitate, day 2) moles of Percent Yield Trial 1 30.0mL of 0.250M CaCl2 15.0mL of 0.750M Na2CO3 NaCO3: 0.751g .56g 1.179 Trial 1 moles of caclz= Molarity x volume (2) 20.250 mol/x30.0ml Calculations For each trial, show the theoretical yield of Calcium Carbonate produced based on your limiting reactant and amounts of each reactant used. CaCl₂(aq) + Na₂CO3(aq) +CaC0₂(s) + 2 NaCl(aq) 0.00750 mol/cacl2 x mol caco 3-0.00750 mol cacoz Imolcacız 1000 mx/14 0.750 mol/// XI5.0ML 1000 mily -0.01125mol-0.0113mol Trial 2 -0.00750mol molar mass of calo₂ = 100.09 g/mol Theoretical yeild of Trial 2 moles of cach 20.250 mol/, x50.0ml. 1000 mk 50.0mL of 0.250M CaCl2 10.0mL of 0.750M Na2CO3 -=0.0125 mol 0.751g .53 1.179 r . CaCo3=0.00750 molx100.09 9/ 19/ тоб =0.7519 moles of Naloz=0.750 mol/L x 10.0ML -0.00750mal 0.00750 molx100-099/mol = 0.7 =0.7519 1000 ML/L Imol Na₂CO3 molex molarmass: Theoretical yeild 0.00750molaco 3 x 1 mol CaCo3=0.00750 mol cacos
Transcribed Image Text:also D O Chem 105 Online recrystallize-which would add an additional mass on the filter paper when dried. that all the spectator ions are rinsed off the filter paper and precipitate and not /7. Carefully remove the filter paper (it will still be very moist) and place it on a paper towel to dry overnight. A sunny window is a happy medium for wet filter paper as well. 8. Repeat the process one more time for a second trial. This time you will measure 10.0mL of 0.750M Na₂CO3 and 50.0mL of 0.250M CaCl₂ into a new plastic cup.. Don't forget your documentation! Data Table If you are cramped for time, an oven will work set at 200-225°F. Set the wet filter paper on a baking sheet and place in the oven. Check it regularly to not burn the filter paper. Data Entry Quantities Used Theoretical Yield of Precipitate (record here, show calculations below table) Mass of Filter Paper BEFORE experiment Mass of DRY Filter Paper and Precipitate (day 2) Mass of Calcium Carbonate (Precipitate, day 2) moles of Percent Yield Trial 1 30.0mL of 0.250M CaCl2 15.0mL of 0.750M Na2CO3 NaCO3: 0.751g .56g 1.179 Trial 1 moles of caclz= Molarity x volume (2) 20.250 mol/x30.0ml Calculations For each trial, show the theoretical yield of Calcium Carbonate produced based on your limiting reactant and amounts of each reactant used. CaCl₂(aq) + Na₂CO3(aq) +CaC0₂(s) + 2 NaCl(aq) 0.00750 mol/cacl2 x mol caco 3-0.00750 mol cacoz Imolcacız 1000 mx/14 0.750 mol/// XI5.0ML 1000 mily -0.01125mol-0.0113mol Trial 2 -0.00750mol molar mass of calo₂ = 100.09 g/mol Theoretical yeild of Trial 2 moles of cach 20.250 mol/, x50.0ml. 1000 mk 50.0mL of 0.250M CaCl2 10.0mL of 0.750M Na2CO3 -=0.0125 mol 0.751g .53 1.179 r . CaCo3=0.00750 molx100.09 9/ 19/ тоб =0.7519 moles of Naloz=0.750 mol/L x 10.0ML -0.00750mal 0.00750 molx100-099/mol = 0.7 =0.7519 1000 ML/L Imol Na₂CO3 molex molarmass: Theoretical yeild 0.00750molaco 3 x 1 mol CaCo3=0.00750 mol cacos
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