mass of 4 kg stretches a spring 16 cm. The mass is acted on by an external force of 2 sin(4) N (newtons) and moves in a medium hat imparts a viscous force of 6 N when the speed of the mass is 2 cm/s. If the mass is set in motion from its equilibrium position with in initial velocity of 4 cm/s, formulate the initial value problem describing the motion of the mass. Assume that g = 9.8 m 4u"' + 6u' + 245u = 2sin(2), (0) = 0. '(0) = 0.04. uin meters. 4u" + 300u +245u2sin( sin(). (0) = 0, '(0) = 0.04, uin meters. 4u" + 6 +2.45u = 2sin( sin(). (0) = 0, '(0) = 0.04. uin meters. 4 +300+245u2sin( in().u(0) = 0.04, u'(0) = 0, 2sin().u(0) = 0. (0) = 0.04, O4u" +300+ 2.45u = win meters. uin meters.

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Chapter2: Second-order Linear Odes
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A mass of 4 kg stretches a spring 16 cm. The mass is acted on by an external force of 2 sin(4) N (newtons) and moves in a medium
that imparts a viscous force of 6 N when the speed of the mass is 2 cm/s. If the mass is set in motion from its equilibrium position with
an initial velocity of 4 cm/s, formulate the initial value problem describing the motion of the mass. Assume that g = 9.8
m
4u" + 6 + 245u = 2sin(
4u" + 300u +245u= 2sin(
O4u" + 6 +2.45u = 2sin(
4u" + 300u +245u= 2sin(
(2), u(0) = 0. u'(0) = 0.04, uin meters.
sin().u(0) = 0, u' (0) = 0.04, uin meters.
sin().u(0) = 0. (0) = 0.04, uin meters.
n(), u(0) = 0.04, u'(0) = 0, win meters.
4u" + 300u' +2.45u = 2sin().u(0) = 0, '(0) 0.04, win meters.
Transcribed Image Text:A mass of 4 kg stretches a spring 16 cm. The mass is acted on by an external force of 2 sin(4) N (newtons) and moves in a medium that imparts a viscous force of 6 N when the speed of the mass is 2 cm/s. If the mass is set in motion from its equilibrium position with an initial velocity of 4 cm/s, formulate the initial value problem describing the motion of the mass. Assume that g = 9.8 m 4u" + 6 + 245u = 2sin( 4u" + 300u +245u= 2sin( O4u" + 6 +2.45u = 2sin( 4u" + 300u +245u= 2sin( (2), u(0) = 0. u'(0) = 0.04, uin meters. sin().u(0) = 0, u' (0) = 0.04, uin meters. sin().u(0) = 0. (0) = 0.04, uin meters. n(), u(0) = 0.04, u'(0) = 0, win meters. 4u" + 300u' +2.45u = 2sin().u(0) = 0, '(0) 0.04, win meters.
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