Mark all of the strings below it matches. Only consider full-string (not substring) matches. /(wfsz\t*)*dvuf trvjssfm.*[!\.]/ \t matches whitespace a) dvuf trvjssfm. b) wfsz trvjssfm. c) wfsz wfsz dvuf trvjssfm. d) wfsz dvuf trvjssfm pg eppn! e) wfszwfszwfszdvuf trvjssfm!
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Mark all of the strings below it matches. Only consider full-string (not substring) matches.
/(wfsz\t*)*dvuf trvjssfm.*[!\.]/
\t matches whitespace
a) dvuf trvjssfm.
b) wfsz trvjssfm.
c) wfsz wfsz dvuf trvjssfm.
d) wfsz dvuf trvjssfm pg eppn!
e) wfszwfszwfszdvuf trvjssfm!
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- Write in C Language Frequent Letter Your Facebook account has just been hacked and you want to change its password. To create a strongpassword, Facebook just recommended you two strings S and T, each contains N lowercase English letters. You want to choose a password containing N lowercase English letters such that the i th character is either the i th character of S or the i th character of T. For example, if S = icyz and T = ixpc, then there are 8 different passwords that you can choose: icyz, icyc, icpz, icpc, ixyz, ixyc, ixpz, ixpc. The strength of your password is defined as the number of occurences of the most frequent letter. For example, the strength of icyz is 1 and the strength icpc is 2. You are wondering what is the strength of the strongest password that you can choose.1. Even Strings: Strings between 10 and 20 characters (inclusive) which have even lengths. o The allowed characters are not specified, and should be considered unrestricted -- maybe there is something in regex for this? o Examples: automobile, i<3pancakes14! o Non-Examples: 6chars), i<3pancakes13#include <stdio.h> #include <string.h> int IsPasswordOkay(char* pass) { char Password[12]; strcpy(Password, pass); if (!strcmp(Password, "goodpass")) return(1); else return(0); } int main(int argc, char **argv) { int PwStatus; if (argc < 2) { printf("Input your password\n"); return(-1); } PwStatus = IsPasswordOkay(argv[1]); if (PwStatus == 0) { printf("Acces denied"); return(-1); } else { printf("Access granted"); return(1); } } Write a function to conduct input validation to secure the smallest buffer. You may call this function void SecurePasswordBuffer(const char *arg).
- •is Valid Phone Number(): ReturnsTrue if the provided phone number (represented as a string) is cor-rectly formatted, otherwiseFalse. To be considered correctly formatted, phone numbers must bewritten as###-###-####, where#is a digit between 0 and 9 .•validatePhoneBook(): A phone book is a list where each entry is a phone book record (represented asa dictionary; see below for more details). This function checks each phone book record in the phonebook for correctly formatted phone numbers.A phone book record is a dictionary which initially has two keys: the key"name"mapped to thecontact’s name (string) and the key"phone number"mapped to that contact’s phone number (alsoa string).validatePhoneBook()adds a new key"valid"to the record with the valueTrueif the phonenumber is formatted correctly, otherwiseFalse. 1. Write white-box and black-box tests for the function is ValidPhoneNumber(). You should do this with-out Python, either on paper, or in a simple document. Don’t worry about…Let L = {ab, aa, baa}. Which of the following strings are in L* and L4: abaabaaabaa , aaaabaaaa , baaaaabaaaab , baaaaabaaGiven the code:string s;cout << "Enter a string of any length: ";cin >> s; Write a few lines of code including a loop that will count and print the number of spaces in the string s using indexes.Note that s can be a string of any length.Example Output 1Enter a string of any length: Hi, how are you?3Example Output 2Enter a string of any length: I am going out tonight.4
- Q2 Let L = {b, abb, bba}. Which of the following strings is not a member of L*? ΟΛ O bababb bbbaabb O bbbbababbabbTwo String values are passed as input. Find if the second string s2 is a substring of the first strings1. If it is, print the index of the first occurrence.Else print -1.Inputmake123India123Output4*/#include<iostream>#include<string.h>using namespace std;int isSubstring(string s1, string s2) { int temp,j; for(int i=0;s1[i]!='\0';i++) { j=0; if(s1[i]==s2[j]) { temp=i+1; while(s1[i]==s2[j]) { i++; j++; } if(s2[j]=='\0') { return temp-1; } else { i=temp; temp=0; } } } if(temp==0) return -1;} int main(int argc, char const *argv[]){ string s1,s2; getline(cin,s1); getline(cin,s2); int res = isSubstring(s1,s2); if(res==-1) cout<<res; else cout<<"Found at index: "<<res;./*** Adds letterGuessed to the current String updateLetterBoard* @param usedLetterBoard* @param letterGuessed* @param first* @return updateLetterBoard with letterGuess appended. */public static String updateLetterBoard(String usedLetterBoard, char letterGuessed, boolean first) {
- get_nth_word_from_string(s, n): This function takes a string s and a non-negative integer n as input. The string s may contain substrings of text separated by commas. The function should return the n’th comma-separated substring. We will start counting at 0, so if n=0, then the first substring should be returned (i.e., everything before the first comma, if there is such a comma); if n=1, then the second substring should be returned (i.e., everything between the first comma and second comma, if there is such a comma); and so on. If there is no n’th substring in s, then the empty string should be returned. Note: You may use the string count method in this function. Note: If a space follows a comma, do not include the space as part of the substring to be returned. >>> get_nth_word_from_string("dreary, pondered, weak, weary", 0) 'dreary'get_nth_word_from_string(s, n): This function takes a string s and a non-negative integer n as input. The string s may contain substrings of text separated by commas. The function should return the n’th comma-separated substring. We will start counting at 0, so if n=0, then the first substring should be returned (i.e., everything before the first comma, if there is such a comma); if n=1, then the second substring should be returned (i.e., everything between the first comma and second comma, if there is such a comma); and so on. If there is no n’th substring in s, then the empty string should be returned. Note: You may use the string count method in this function. Note: If a space follows a comma, do not include the space as part of the substring to be returned.#include <iostream>#include <string.h>using namespace std; //hasHelpOption() definition int hasHelpOption(int argc, char **argv){ for(int i=0;i<argc;++i) if(((strcmp(argv[1],"--help"))==0) || ((strcmp(argv[1],"/help"))==0) || ((strcmp(argv[1],"/?"))==0)) return 1; else return 0;} //main function int main(int argc, char** argv) { int x=0; cout << "You have entered: "<<argv[1]; x=hasHelpOption(argc,argv); if(x==1) cout<<"\nTrue"; else cout<<"\nFalse"; return 0; } what should i correct for the code?