Many metal ions are precipitated from a solution by the sulfide ion. As an example, consider treating a solution of copper(II) sulfate with sodium sulfide solution: CuSO4(aq) + Na2S(ag) → CuS(s) + Naz SO4 (aq) What volume of 0.102 M Na2S solution would be required to precipitate all of the copper(II) ion from 23.0 mL of 0.122 M CuSO4 solution? Volume = mL
Many metal ions are precipitated from a solution by the sulfide ion. As an example, consider treating a solution of copper(II) sulfate with sodium sulfide solution: CuSO4(aq) + Na2S(ag) → CuS(s) + Naz SO4 (aq) What volume of 0.102 M Na2S solution would be required to precipitate all of the copper(II) ion from 23.0 mL of 0.122 M CuSO4 solution? Volume = mL
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter4: Chemical Reactions In Solution
Section: Chapter Questions
Problem 4.91QE
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![Many metal ions are precipitated from a solution by the sulfide ion. As an example, consider treating a solution of copper(II) sulfate with sodium sulfide
solution:
CuSO4 (ag) + Naz S(aq) → CuS(s)+ Na2SO4(ag)
What volume of 0.102 M Na2S solution would be required to precipitate all of the copper(II) ion from 23.0 mL of 0.122 M CuSO4 solution?
Volume =
mL](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1972818e-7493-4b2a-afbd-f9c326deed5e%2F02d0d874-4312-4944-80d5-84c33a32f089%2Fh1ueq9p_processed.png&w=3840&q=75)
Transcribed Image Text:Many metal ions are precipitated from a solution by the sulfide ion. As an example, consider treating a solution of copper(II) sulfate with sodium sulfide
solution:
CuSO4 (ag) + Naz S(aq) → CuS(s)+ Na2SO4(ag)
What volume of 0.102 M Na2S solution would be required to precipitate all of the copper(II) ion from 23.0 mL of 0.122 M CuSO4 solution?
Volume =
mL
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