Phosphoryl chloride, POCl3(g), is used in the manufacturing of flame retardants. It is manufactured in anequilibrium process in which phosphorus trichloride reacts with nitrogen dioxide to form POCl3(g)and NO(g)according to the following equation:PCl3 (g) + NO2 (g) ⇌ POCl3 (g) + NO (g)The Keq for this reaction at 800 Kc is 3.88. If 1.35 mol PCl3 (g) and 1.74 mol NO2 (g) are placed into a 2.5 Lcontainer, how many moles will there be of each gas when the reaction reaches equilibrium? IсEPhosphoryl chloride, POCI3(g), is used in the manufacturing of flame retardants. It is manufactured in anequilibrium process in which phosphorus trichloride reacts with nitrogen dioxide to form POCI3(g)and NO(g)according to the following equation:PCl3 (g) + NO₂ (g) = POCI3 (g) + NO (g)The Keg for this reaction at 800 K is 3.88. If 1.35 mol PCI; (g) and 1.74 mol NO₂ (g) are placed into a 2.5 Lcontainer, how many moles will there be of each gas when the reaction reaches equilibriumPCI 3 (g)+NO₂ (g)=POCI3(g)NO(g)Kc = 3.88

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Answered: manufactured in an equilibrium process…

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Phosphoryl chloride, POCl3(g), is used in the manufacturing of flame retardants. It is manufactured in an
equilibrium process in which phosphorus trichloride reacts with nitrogen dioxide to form POCl3(g)and NO(g)
according to the following equation:

PCl3 (g) + NO2 (g) ⇌ POCl3 (g) + NO (g)

The Keq for this reaction at 800 Kc is 3.88. If 1.35 mol PCl3 (g) and 1.74 mol NO2 (g) are placed into a 2.5 L
container, how many moles will there be of each gas when the reaction reaches equilibrium?

I
с
E
Phosphoryl chloride, POCI3(g), is used in the manufacturing of flame retardants. It is manufactured in an
equilibrium process in which phosphorus trichloride reacts with nitrogen dioxide to form POCI3(g)and NO(g)
according to the following equation:
PCl3 (g) + NO₂ (g) = POCI3 (g) + NO (g)
The Keg for this reaction at 800 K is 3.88. If 1.35 mol PCI; (g) and 1.74 mol NO₂ (g) are placed into a 2.5 L
container, how many moles will there be of each gas when the reaction reaches equilibrium
PCI 3 (g)
+
NO₂ (g)
=
POCI3(g)
NO(g)
Kc = 3.88

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