Makers of a well-known toy for kids has an average of 735 orders per week to be delivered to different establishments. However, after the Christmas season, orders appear to have slowed down. Suppose the manager of the toy company randomly selects 55 weeks and finds a sample mean order of 589 with a standard deviation of 6.2 orders. Test to determine whether the average number of orders slow down by using a= 0.05. Which of the following is the claim of the hypothesis?
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Makers of a well-known toy for kids has an average of 735 orders per week to be delivered to different establishments. However, after the Christmas season, orders appear to have slowed down. Suppose the manager of the toy company randomly selects 55 weeks and finds a sample mean order of 589 with a standard deviation of 6.2 orders. Test to determine whether the average number of orders slow down by using a= 0.05. Which of the following is the claim of the hypothesis?
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- A fast-food chain claims one medium order of its onion rings weighs 114 grams. Patrice thinks she is getting less than what the restaurant advertises. She weighs the next 16 random orders of onion rings before she eats them and finds the sample mean is 112.4 grams and the standard deviation is 7.63 grams. What conclusion can be drawn a = 0.10? O Patrice does not have sufficient evidence to reject the fast-food chain's claim. O Patrice has sufficient evidence to reject the fast-food chain's claim. O There is not sufficient evidence to prove the fast-food chain advertisement is true. O There is sufficient evidence to prove the fast-food chain advertisement is false. O There is not sufficient data to reach any conclusion.Insurance Company A claims that its customers pay less for car insurance, on average than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 11 people who buy insurance from Company A, the mean cost is $150 per month with a standard deviation of $14. For 14 randomly selected customers of Company B, you find that they pay a mean of $158 per month with a standard deviation of $12. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places.Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 13 people who buy insurance from Company A, the mean cost is $150 per month with a standard deviation of $19. For 9 randomly selected customers of Company B, you find that they pay a mean of $157 per month with a standard deviation of $16. Assume that both populations are approximately normal and that the population variances are equal to test Company A's claim at the 0.05 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
- Derby Leicester is a city planner preparing for a meeting with the mayor. He would like to show that the population mean age of the houses on Lincoln Street is less than the population mean age of the houses on Maple Street so that more resources are allotted to repair Maple Street. Derby uses a previous study to assume that the population standard deviation for the ages of the houses is 7.72 years for Lincoln Street and 8.39 years for Maple Street. Due to limited time, Derby randomly selects a sample of houses on Lincoln Street and the houses on Maple Street from the city’s property records and then records the age of each house in years. The results of the samples are shown in the table below. Explain whether a hypothesis test for the difference between two means of independent samples is appropriate, and if so, determine the null and alternative hypotheses for this hypothesis test, where μ1 is the population mean age of the homes on Lincoln Street and μ2 is the population mean age…A pizza delivery chain advertises that it will deliver your pizza in 2020 minutes from when the order is placed. Being a skeptic, you decide to test and see if the mean delivery time is actually more than 2020 minutes. For the simple random sample of 88 customers who record the amount of time it takes for each of their pizzas to be delivered, the mean is 22.222.2 minutes with a standard deviation of 3.13.1 minutes. Assume that the population distribution is approximately normal. Perform a hypothesis test using a 0.0250.025 level of significance. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places. Step 3 of 3 : Draw a conclusion and interpret the decision.Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 37 randomly selected people who train in groups, and finds that they run a mean of 47.7 miles per week. Assume that the population standard deviation for group runners is known to be 3.3 miles per week. She also interviews a random sample of 49 people who train on their own and finds that they run a mean of 49.4 miles per week. Assume that the population standard deviation for people who run by themselves is 4.4 miles per week. Test the claim at the 0.10 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
- Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 7 people who buy insurance from Company A, the mean cost is $150 per month with a standard deviation of $16. For 12 randomly selected customers of Company B, you find that they pay a mean of $160 per month with a standard deviation of $14. Assume that both populations are approximately normal and that the population variances are equal to test Company A's claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.You are the manager of a restaurant that delivers pizza to college dormitory rooms. You have just changed your delivery process in an effort to reduce the mean time between the order and completion of delivery from the current 25 minutes. A sample of 36 orders using the new delivery process yields a sample mean of 22.4 minutes and a sample standard deviation of 6 minutes. Perform a hypothesis test to determine if there’s evidence that the population mean delivery time has been reduced below the previous population mean value of 25 minutes by answering the following questions: (a) What are the null and alternate hypotheses for this test? (b) What is the value of the test statistic for this test? (c) Using the critical value approach, at the 0.05 level of significance, what is the decision rule? (d) What is your conclusion in context of the problem? (Answer this question in a complete sentence(s) and include why, referring to the decision rule.) (e) Using the p-value approach, at the…Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
- Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 13 people who buy insurance from Company A, the mean cost is $150 per month with a standard deviation of $19. For 9 randomly selected customers of Company B, you find that they pay a mean of $157 per month with a standard deviation of $16. Assume that both populations are approximately normal and that the population variances are equal to test Company A's claim at the 0.05 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho: M₁ = μ₂ Ha:M₁ •H₂Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 15 people who buy insurance from Company A, the mean cost is $154 per month with a standard deviation of $13. For 11 randomly selected customers of Company B, you find that they pay a mean of $159 per month with a standard deviation of $16. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.02 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places.Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 12people who buy insurance from Company A, the mean cost is $153 per month with a standard deviation of $16. For 15 randomly selected customers of Company B, you find that they pay a mean of $160 per month with a standard deviation of $10. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. H0: μ1=μ2 Ha: μ1_____μ2 Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places Step 3 of…
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