# 2-to-4 Line Decoder Circuit## DescriptionThe image displays a logic circuit of a 2-to-4 line decoder, and the goal is to create a truth table based on the given circuit. A 2-to-4 line decoder uses two input lines (A and B) and one enable line (E) to generate four outputs (\(D_0\), \(D_1\), \(D_2\), \(D_3\)).### Circuit Breakdown- **Inputs**: - A - B - E (Enable)- **Outputs**: - \(D_0\) - \(D_1\) - \(D_2\) - \(D_3\)### Logic GatesThe circuit consists of inverters (NOT gates) and NAND gates.### ExplanationFor a 2-to-4 decoder:- When the enable input (E) is `0`, all outputs are `0`.- When the enable input (E) is `1`: - \(D_0\) is `1` if A = `0` and B = `0`. - \(D_1\) is `1` if A = `0` and B = `1`. - \(D_2\) is `1` if A = `1` and B = `0`. - \(D_3\) is `1` if A = `1` and B = `1`.### Truth Table FormatThe truth table consists of the possible values of inputs A, B, and E, and the corresponding outputs (\(D_0\), \(D_1\), \(D_2\), \(D_3\)).#### Diagram ExplanationThe given diagram shows inverters connected to inputs A, B, and E. These, along with their original inputs, are fed into four NAND gates to determine the outputs \(D_0\), \(D_1\), \(D_2\), and \(D_3\).## Truth TableBelow is the format for constructing the truth table:| E | A | B | \(D_0\) | \(D_1\) | \(D_2\) | \(D_3\) ||---|---|---|--------|--------|--------|--------|| 0 | 0

To create truth table for the given 2-4 line decoder circuit

Make the truth table for given 2-to-4 line decoder circuit, as shown in sample: A B E Do Do D₁ D₂ D3 Answer (7 characters separated by a space in each row): 000 0000 000 0.000 000 0000 A B Do D1 D2 D3

Make the truth table for given 2-to-4 line decoder circuit, as shown in sample: A B E Do Do D₁ D₂ D3 Answer (7 characters separated by a space in each row): 000 0000 000 0.000 000 0000 A B Do D1 D2 D3

Programming Logic & Design Comprehensive

9th Edition

ISBN:9781337669405

Author:FARRELL

Publisher:FARRELL

Chapter4: Making Decisions

Section: Chapter Questions

Problem 4RQ

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