Sample Input 5 3 89 90 78 93 80 90 91 85 88 86 91 92 83 89 90.5 Sample Output 90.0 91.0 82.0 90.0 85.5 Explanation Marks obtained by student 1: 89, 90, 91 Average marks of student 1: 270/3 = 90 Marks obtained by student 2: 90, 91, 92 Average marks of student 2: 273/3 = 91 Marks obtained by student 3: 78, 85, 83 Average marks of student 3: 246/3 = 82 Marks obtained by student 4: 93, 88, 89 Average marks of student 4: 270/3 = 90 Marks obtained by student 5: 80, 86, 90.5 Average marks of student 5: 256.5/3 = 85.5

Sample Input 5 3 89 90 78 93 80 90 91 85 88 86 91 92 83 89 90.5 Sample Output 90.0 91.0 82.0 90.0 85.5 Explanation Marks obtained by student 1: 89, 90, 91 Average marks of student 1: 270/3 = 90 Marks obtained by student 2: 90, 91, 92 Average marks of student 2: 273/3 = 91 Marks obtained by student 3: 78, 85, 83 Average marks of student 3: 246/3 = 82 Marks obtained by student 4: 93, 88, 89 Average marks of student 4: 270/3 = 90 Marks obtained by student 5: 80, 86, 90.5 Average marks of student 5: 256.5/3 = 85.5

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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