Make an expression for calculating the projection of the force F on the Ox axis
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Make an expression for calculating the projection of the force F on the Ox axis
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- The 5.9-KN force F is applied at point A. (a) Compute the moment of F about point O, expressing it both as a scalar (positive if CCW, negative if CW) and as a vector quantity. (b) Determine the coordinates of the points on the x- and y-axes about which the moment of F is zero. Assume XA = 1.2 m, YA-1.8 m, a-6, b = 12. y, m A(x, y) j+ k) kN-m Answers: (a) Scalar: Vector: On the x axis: On the y axis: (6) Mo i Moi y= i -x, m m E kN-m i+ iConsider the force vector F=<1,1,1/2>. If the magnitude of the torque T=OP*F is equal to the area of the equilateral triangle formed by the origin, P, and (1,-1,1), then determine the acute angle formed by OP and F. Give your answer in degrees.What relative orientation of vectors results in a minimum value of magnitude of the cross product? What relative orientation of vectors results in a dot product of zero?
- I need help with this problem and an explanation for the solution described below. (University Physics 1: Vectors)à ở từ if a = 2.8i+ 5.7 j – 8.1k, = b = − 4.9î + 4.4ĵ + 3.8k, and What are (a) the x component, (b) the y component, and (c) the z component of 7 1.8î + 2.8ĵ + 4.6k . (d) Calculate the angle between and the positive z axis. (e) What is the component of a along the direction of b? (f) What is the magnitude of the component of a perpendicular to the direction of b but in the plane of a and b? =Can you please do 4, 5 and 6. Thank you