Magnetic resonance imaging (MRI) makes it possible to see details of soft tissue that aren’t visible in x-ray images. Yet soft tissue isn’t a magnetic material (it’s not attracted to a magnet). How does MRI work?
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Magnetic resonance imaging (MRI) makes it possible to see details of soft tissue that aren’t visible in x-ray images. Yet soft tissue isn’t a magnetic material (it’s not attracted to a magnet). How does MRI work?
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- An electric current I = 0.45 A is flowing in an infinitely long wire. Randomized Variables I= 0.45 A Part (a) If the distance from point A to the wire is a as in the figure, write an equation for the magnitude of the magnetic field [B| generated by the current at A in terms of I and a. Part (b) If a = 0.045 m, calculate the numerical value of B in tesla.Magnetic resonance imaging (MRI) is one of the most useful and rapidly growing medical imaging tools. It non-invasively produces two-dimensional and three-dimensional images of the body that provide important medical information with none of the hazards of x-rays. MRI is based on an effect called nuclear magnetic resonance (NMR) in which an externally applied magnetic field interacts with the magnetic fields of nuclei of certain atoms, particularly those of hydrogen (protons). The external magnetic field is created by a large coil. This field interacts with the hydrogen atoms in the patient's body to form images. a) To see why an MRI utilizes iron to increase the magnetic field created by a coil, calculate the current needed in a 420-loop-per-meter circular coil 0.66 m in radius to create a 1.3 T field (typical of an MRI instrument) at its center with no iron present. /= A Introducing ferromagnetic materials inside coils greatly increases the magntic field inside the coil for a small…Use the following constants if necessary. Coulomb constant, k = 8.987 x 10° N · m² /C².Vacuum F/m. -12 permitivity, €o = 8.854 × 10 Magnetic Permeability of vacuum, Ho = 12.566370614356 x 10¬7 H /m. Magnitude of the Charge of one electron, e = -1.60217662 × 10 19 C. Mass of one -31 electron, me = 9.10938356 × 10' Unless specified otherwise, each symbol carries their usual meaning. For example, µC means тіcro coulomb. kg. Vz a C {Ry RS R2 R3 R6 R7 You have given the above diagram of a resistor network. The numerical values of the resistors are R2 = 4 kN, R3 = 6 kN, R4 = 4 kN, R5 = 8 kN, R6 = 8 kN, R7 = 2 kN. And the e.m.f s are V1 9.0 volts, V2 = 14.0 volts, V3 = 10.0 volts, a) Find the equivalent resistance across the terminal cd. equivalent resistance Give your answer up to at least three significance digits.
- 4. An ionized deuteron (a particle with a +e charge) passes through a velocity selector whose magnetic and electric fields have magnitudes of 40.0 mT and 6.70 kV/m, respectively. Find the speed of the ion to undeflected. m/s VISS (9JS 09.09 $$160 ssfove through the selectorA singly-ionized methane atom (mass of 2.66×10-26 kg) follows the dotted path shown when sent into a mass spectrometer with a uniform magnetic field. Assume that the magnetic field in the mass spectrometer is caused by a large solenoid with a radius 54 cm, that is 0.6 m long and made up of 5900 loops. If a 9 T magnetic field is needed to detect a certain compound, how much current needs to be run through the coils of the solenoid? 7.28×102 A 6.56×102 A 1.21×103 A 2.43×107 A 1.11×103 AThe Bainbridge spectrometer works by ionizing particles, sending them through a velocity selector, and then detecting a given charge-to-mass ratio based on its trajectory in a uniform magnetic field (See Ch 11.7 in your book). Suppose your spectrometer works by altering the electric field of the velocity selector to scan for ions. If a singly-charged ion of mass 140.9 amu required an electric field of 1.9 N/C, what electric field would be necessary to detect a doubly-charged ion of mass 161.9? Give your answer in units of N/C.