The answer is already there, however, I need an explanation of why the answer is what it is. (7.)oa 300 Turn coil of length 20.0 cm and a-radius of 1.50 cm carries a current of 2.0 Amps,0.015mMoIBía) B₁ = 125 Prséمہ279.) Find the initial magnetic Field (Use Amperesowly gb.) the current is then Increased slowly to 5,0 Amps over9.00 seconds. What is the value of the magneticField at 9.0 seconds!b) PEARN=B₁B. - Mo I (471 x 10 = A 2) (5.0A)I=2.0 AAuf (SA-2A) =3Ac.) Find the Adorage induced Emt(&') of the coil during the9.0 Seconds.NBAAtO10-7411X10/12 (2.0A)2π (0.015m)Beenr =1,50cmc) E= - NA² = -NBA-At22π (・015m) = 6.66x10³T*/ (04-18;)), ² = π (0,015m) ² = 7.068x10A/Bf-Bi).ет20.0 cm=/2.66x10-ST-42(سم)8-300 (6.66x10-57-2,66x107) (7.068 x15%²9s9.42 x 10

Answered: Image /qna-images/answer/09c6d9d8-0014-4cd5-9997-7e50cd518431.jpg

Answered: = magnetic Field (

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