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(7.) o a 300 Turn coil of length 20.0 cm and a -radius of 1.50 cm carries a current of 2.0 Amps, 0.015m MoI Bí a) B₁ = 125 Pr sé مہ27 9.) Find the initial magnetic Field (Use Amperes owly g b.) the current is then Increased slowly to 5,0 Amps over 9.00 seconds. What is the value of the magnetic Field at 9.0 seconds! b) PEAR N = B₁ B. - Mo I (471 x 10 = A 2) (5.0A) I=2.0 A Auf (SA-2A) =3A c.) Find the Adorage induced Emt(&') of the coil during the 9.0 Seconds. NBA At O 10-7 411X10/12 (2.0A) 2π (0.015m) Been r = 1,50cm c) E= - NA² = -NBA- At 2 2π (・015m) = 6.66x10³T */ (04-18;)), ² = π (0,015m) ² = 7.068x10 A/Bf-Bi). ет 20.0 cm =/2.66x10-ST -4 2 (سم) 8 -300 (6.66x10-57-2,66x107) (7.068 x15%² 9s 9.42 x 10
Transcribed Image Text:(7.) o a 300 Turn coil of length 20.0 cm and a -radius of 1.50 cm carries a current of 2.0 Amps, 0.015m MoI Bí a) B₁ = 125 Pr sé مہ27 9.) Find the initial magnetic Field (Use Amperes owly g b.) the current is then Increased slowly to 5,0 Amps over 9.00 seconds. What is the value of the magnetic Field at 9.0 seconds! b) PEAR N = B₁ B. - Mo I (471 x 10 = A 2) (5.0A) I=2.0 A Auf (SA-2A) =3A c.) Find the Adorage induced Emt(&') of the coil during the 9.0 Seconds. NBA At O 10-7 411X10/12 (2.0A) 2π (0.015m) Been r = 1,50cm c) E= - NA² = -NBA- At 2 2π (・015m) = 6.66x10³T */ (04-18;)), ² = π (0,015m) ² = 7.068x10 A/Bf-Bi). ет 20.0 cm =/2.66x10-ST -4 2 (سم) 8 -300 (6.66x10-57-2,66x107) (7.068 x15%² 9s 9.42 x 10
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