Magnetic Field of a Point Charge 5. A proton has the following conditions: Charge 1.6 x 10-19C (2.0,0.0,0.0)m (0.0,1.2 × 10®, 0.0)m/s (0.0,0.0,0.0)m/s² Position Velocity Acceleration What is the vector magnetic field created at the location (0.0,3.0,0.0)?
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- Ords 8. An electron is moving through a magnetic field in a direction perpendicular to the field as shown below. The charge is moving with a speed of = 3.5x105 and it experiences a force of F = 1.79×10-13 N. English (US) What is the magnitude and direction of the magnetic field? The charge of an electron is qe = -1.6x10-19 C. v MacBook P 5A current-carrying wire is in a B-field and experiences a magnetic force (P>0). The current direction is shown below. Choose all the vectors that could represent the B-fleid vector. WebAssign Plot Current direction 70 B-field 50 20 MacBook AirQuestion 12 Charged spheres I, II, and III are located as shown below. = −6.50 µC 1 41 20.0 cm The net electrostatic force on sphere I is: 911 = +3.50 µC II 10.0 cm 9m=+2.80μC Question 13. The path of a charged particle travelling perpendicularly through a uniform magnetic field is deflected due to and the speed of the charged particle will 77 O L G C
- Q1) Example 11.1: Page No. 498: (Practice) An alpha-particle of charge 3.2 x 10 19 C moves through a uniform magnetic field of 1.5 T. What is the maximum magnetic force on the alpha-particle when it is moving with a speed of 5.0 x 10 m/s? Q2) Problem 23: Page No. 525: (Practice) An electron moving at 4.00 x 10 m/s in a 1.25-T magnetic field experiences a magnetic force of 1.40 x 10 N. What angle does the velocity of the electron make with the magnetic field? Q3) Problem 33: Page No. 526: An alpha-particle (m-6.64x10"kg, q=3.2×101°C) travels in a circular path of radius 25 cm in a uniform magnetic field of magnitude 1.5 T. (a) What is the speed of the particle? (b) What is the kinetic energy in electron volts? (1 electron-volt = 1.602x10 9 joule) Q4) Problem 25: Page No. 525: (Practice) A cosmic-ray electron moves at 7.5x10 m/s perpendicular to Earth's magnetic field at an altitude where the ficld strength is 0.1 G. What is the radius of the circular path the electron follows? F00…A proton moves in a helical path at speed v = 6.10 × 107 m/s high above the atmosphere, where Earth’s magnetic field has magnitude B = 1.30 × 10−6 T. The proton’s velocity makes an angle of 25.0° with the magnetic field. The mass of the proton is 1.673×10−27 kg. Find the radius of the helix. *NEED ANSWER IN km*02A) a proton moves at 7.50 x 10 perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radiusim What is the field strength? (a) at what speed will a proton move in a circular path of the same radius as the electron (b) What would the radius be if the proton had the same momentum?