magine that you’ve been invited to try out a new hoversuit , and here's how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they’ve charged the sheet up to a uniform charge density of 3.85 x 10^-6 C. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. Agan, suppose you were hovering stationary, except now with sheet charge density 3.85 x 10^-6 C and your mass including the suit 66.4 kg. Suppose that while you were hovering, someone threw you a rock of mass 6.6 kg, and that you caught it. What would now be your rate of acceleration toward the ground? 8.92 m/s^2 1.16 m/s^2 0.89 m/s^2 9.81 m/s^2
Imagine that you’ve been invited to try out a new hoversuit , and here's how it works: Someone has set
up a large flat sheet, many kilometers across, somewhere on the Earth, and they’ve charged the sheet
up to a uniform charge density of 3.85 x 10^-6 C. You are issued a special suit that you wear, and it has
controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative,
that you might want. The idea is that you can control the amount of electrical repulsion (or attraction)
between the suit and the charged sheet below you. Agan, suppose you were hovering stationary,
except now with sheet charge density 3.85 x 10^-6 C and your mass including the suit 66.4 kg. Suppose
that while you were hovering, someone threw you a rock of mass 6.6 kg, and that you caught it. What
would now be your rate of acceleration toward the ground?
8.92 m/s^2
1.16 m/s^2
0.89 m/s^2
9.81 m/s^2
charge = q = 3.85 x 10-6 C
mass including suit = m1 = 66.4 kg
mass of rock = m2 = 6.6 kg
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