Macmillan Learning The graph shows a heat curve for an unidentified substance discovered by the Mars rover. Temperature (°C) Tfusion = Tvapor 400- 380 - 360 340 320 300 280 260 240 220- 200 180 160 140 120 100- 80 60 40 20 Q = 0- = -20- -40 -60- -80- What is the temperature of fusion, Tfusion, of the substance? 40 80 What is the temperature of vaporization, Tvapor, of the substance? Heat (J) 120 Given a 86.6-g sample of this substance with a specific heat of 50.6 J/(kg-°C), how much heat is required to change its temperature from 180.0 °C to 226.0 °C? °C °C J

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Chapter1: Chemical Foundations
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© Macmillan Learning
The graph shows a heat curve for an unidentified substance discovered by the Mars rover.
Tfusion
Temperature (°C)
Tvapor
400
380
360
340
320
300
280
260
240
220
200
180
160
140
120
100
80-
60
40
20
Q =
0
=
-20
-40
-60
-80
What is the temperature of fusion, Tfusion, of the substance?
40
80
What is the temperature of vaporization, Tvapor, of the substance?
Heat (J)
120
Given a 86.6-g sample of this substance with a specific heat of 50.6 J/(kg-°C), how much heat is required to change its
temperature from 180.0 °C to 226.0 °C?
°℃
°℃
J
Transcribed Image Text:© Macmillan Learning The graph shows a heat curve for an unidentified substance discovered by the Mars rover. Tfusion Temperature (°C) Tvapor 400 380 360 340 320 300 280 260 240 220 200 180 160 140 120 100 80- 60 40 20 Q = 0 = -20 -40 -60 -80 What is the temperature of fusion, Tfusion, of the substance? 40 80 What is the temperature of vaporization, Tvapor, of the substance? Heat (J) 120 Given a 86.6-g sample of this substance with a specific heat of 50.6 J/(kg-°C), how much heat is required to change its temperature from 180.0 °C to 226.0 °C? °℃ °℃ J
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We are given a heating curve for unknown substance found on mars. We need to calculate its melting and boiling points and heat required to raise its temperature from 180.0 °C to 226.0 °C.

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