.5000 moles of steam at 200 degrees celsius was chilled in a ultra low temperature freezer to -90 degreees celsius. if the heat of vaporization of steam is 540. cal/ gram, the heat of fusion of water is 80.0 cal/ gram, the specific heat of steam is .500 cal/ gram -celsius, the specific heat of water is 1.000 cal/ gram- celsius and the specific heat of ice is .500 cal/ gram -celsius, how many kJ of energy is released, assuming no energy loss to the environment? 1 calorie= 4.184 Joules.

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.5000 moles of steam at 200 degrees celsius was chilled in a ultra low temperature freezer to -90 degreees celsius. if the heat of vaporization of steam is 540. cal/ gram, the heat of fusion of water is 80.0 cal/ gram, the specific heat of steam is .500 cal/ gram -celsius, the specific heat of water is 1.000 cal/ gram- celsius and the specific heat of ice is .500 cal/ gram -celsius, how many kJ of energy is released, assuming no energy loss to the environment? 1 calorie= 4.184 Joules. 

 

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9b. 0.5000 moles of steam at 200°C was chilled in a ultra-low temperature freezer to -90°C. If the heat of
vaporization of steam is 540. cal/gram, the heat of fusion of water is 80.0 cal/gram, the specific heat of steam is
0.500 cal/gram-°C, the specific heat of water is 1.000 cal/gram-°C, and the specific heat of ice is 0.500
cal/gram-°C, how many kJ of energy is released, assuming no energy loss to the environment? 1 calorie = 4.184
Joules.
%3D
CUT
Alt.
Transcribed Image Text:9b. 0.5000 moles of steam at 200°C was chilled in a ultra-low temperature freezer to -90°C. If the heat of vaporization of steam is 540. cal/gram, the heat of fusion of water is 80.0 cal/gram, the specific heat of steam is 0.500 cal/gram-°C, the specific heat of water is 1.000 cal/gram-°C, and the specific heat of ice is 0.500 cal/gram-°C, how many kJ of energy is released, assuming no energy loss to the environment? 1 calorie = 4.184 Joules. %3D CUT Alt.
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