Macmillan Learning Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese (IV) oxide. 4 HCl(aq) + MnO₂ (s) MnCl₂(aq) + 2 H₂O(1) + Cl₂(g) A sample of 38.1 g MnO₂ is added to a solution containing 44.3 g HCI. What is the limiting reactant? HC1 MnO₂ What is the theoretical yield of Cl₂? theoretical yield: If the yield of the reaction is 76.3%, what is the actual yield of chlorine? actual yield: g Cl₂ g Cl₂
Macmillan Learning Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese (IV) oxide. 4 HCl(aq) + MnO₂ (s) MnCl₂(aq) + 2 H₂O(1) + Cl₂(g) A sample of 38.1 g MnO₂ is added to a solution containing 44.3 g HCI. What is the limiting reactant? HC1 MnO₂ What is the theoretical yield of Cl₂? theoretical yield: If the yield of the reaction is 76.3%, what is the actual yield of chlorine? actual yield: g Cl₂ g Cl₂
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Preparation of Chlorine Gas via Reaction of Hydrochloric Acid and Manganese(IV) Oxide**
Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide, as described by the following chemical equation:
\[ 4 \text{HCl (aq)} + \text{MnO}_2 \text{(s)} \rightarrow \text{MnCl}_2 \text{(aq)} + 2 \text{H}_2\text{O (l)} + \text{Cl}_2\text{(g)} \]
A sample of 38.1 g of \(\text{MnO}_2\) is added to a solution containing 44.3 g of \(\text{HCl}\).
**Limiting Reactant Determination**
Which of the following is the limiting reactant?
- \(\text{HCl}\)
- \(\text{MnO}_2\)
**Theoretical Yield Calculation**
What is the theoretical yield of \(\text{Cl}_2\)?
- **Theoretical yield:** \_\_\_\_\_\_\_\_\_\_\_\_\_ g \(\text{Cl}_2\)
**Actual Yield Calculation**
If the yield of the reaction is 76.3%, what is the actual yield of chlorine?
- **Actual yield:** \_\_\_\_\_\_\_\_\_\_\_\_\_ g \(\text{Cl}_2\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a54ba52-8823-45a4-bdfc-14d625ac2519%2F0054af33-b2ad-48d4-82e2-113d63d172e8%2Frwg3k5k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Preparation of Chlorine Gas via Reaction of Hydrochloric Acid and Manganese(IV) Oxide**
Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide, as described by the following chemical equation:
\[ 4 \text{HCl (aq)} + \text{MnO}_2 \text{(s)} \rightarrow \text{MnCl}_2 \text{(aq)} + 2 \text{H}_2\text{O (l)} + \text{Cl}_2\text{(g)} \]
A sample of 38.1 g of \(\text{MnO}_2\) is added to a solution containing 44.3 g of \(\text{HCl}\).
**Limiting Reactant Determination**
Which of the following is the limiting reactant?
- \(\text{HCl}\)
- \(\text{MnO}_2\)
**Theoretical Yield Calculation**
What is the theoretical yield of \(\text{Cl}_2\)?
- **Theoretical yield:** \_\_\_\_\_\_\_\_\_\_\_\_\_ g \(\text{Cl}_2\)
**Actual Yield Calculation**
If the yield of the reaction is 76.3%, what is the actual yield of chlorine?
- **Actual yield:** \_\_\_\_\_\_\_\_\_\_\_\_\_ g \(\text{Cl}_2\)
Expert Solution
Step 1
Limiting agent: The reagent which is in smaller in proportion compared to that shown in balanced equation
Number of mol = Mass/molar mass
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