m please, Thanks) (ANSWER PROBLEM 23)

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PROBLEM: VIE-23

BOOK: ENGINEERING THERMOFLUIDS, M. MASSOUD

(You can answer my question even if it's rough or with assumptions, I just need an overview on how to solve this kind of problem please, Thanks)

(ANSWER PROBLEM 23)

23. Regarding neutron-nucleus interaction, so far we dealt with elastic collision
for isotropic and anisotropic scatterings. In this problem, we want to find E’/E for
an inelastic scattering in which the target nucleus absorbs an amount of energy Q.
Use the energy equation, which now accounts for Q and the velocity diagram of
Problem 12 to show that:
1/2
E' A°5? +2A5 cos cOM +1
1+ A
E
(1+ A)²
EA
Transcribed Image Text:23. Regarding neutron-nucleus interaction, so far we dealt with elastic collision for isotropic and anisotropic scatterings. In this problem, we want to find E’/E for an inelastic scattering in which the target nucleus absorbs an amount of energy Q. Use the energy equation, which now accounts for Q and the velocity diagram of Problem 12 to show that: 1/2 E' A°5? +2A5 cos cOM +1 1+ A E (1+ A)² EA
12. The collision in Problems 8 and 9 is described from the point of view of a sta-
tionary observer, referred to as the laboratory (LAB) system. Now, consider a
case were the observer is instead located at the center of momentum of the neutron
and nucleus, referred to as the center of momentum (COM) system. In this case
the total momentum before and after the collision is zero. Show that the velocity
of the center of momentum (which for non-relativistic events is the same as the
center of mass) for the stationary nucleus is given by VcoM = Vn,LAB/(A + 1) where
Vn.LAB is the neutron velocity in the LAB system before collision. Also show that
Vn.COM = A V„LAB/(A + 1) and Vn.COM = - VnLAB/(A + 1) where Vn.COM is the veloc-
ity of the nucleus before the collision in the COM system.
Vn.COM
VN.COM
V
n,COM
COM
N,COM
V COM
сом
YCOM
Vn.COM
Pcom
n,LAB
PLAB
Transcribed Image Text:12. The collision in Problems 8 and 9 is described from the point of view of a sta- tionary observer, referred to as the laboratory (LAB) system. Now, consider a case were the observer is instead located at the center of momentum of the neutron and nucleus, referred to as the center of momentum (COM) system. In this case the total momentum before and after the collision is zero. Show that the velocity of the center of momentum (which for non-relativistic events is the same as the center of mass) for the stationary nucleus is given by VcoM = Vn,LAB/(A + 1) where Vn.LAB is the neutron velocity in the LAB system before collision. Also show that Vn.COM = A V„LAB/(A + 1) and Vn.COM = - VnLAB/(A + 1) where Vn.COM is the veloc- ity of the nucleus before the collision in the COM system. Vn.COM VN.COM V n,COM COM N,COM V COM сом YCOM Vn.COM Pcom n,LAB PLAB
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