A compound has the following data: (see image ) Please show how to draw structure using skeletal structure only. M peak at m/z 228, M + 2 peak at m/z 230 (~1:1 intensity)IR: 3400 – 2500 cm1 (intense, broad), 1710 cm1 (intense, sharp)13C-NMR: there are seven signals3H, doublet2H, m2H, m1H, quartet1H, singlet121084PPM

A 1:1 intensity peaks for M+ and M+2 indicates towards the presence of Bromine atom. This is because bromine exists as two isotopes with almost equal natural abundance that smdiffer in mass by 2 units. IR suggests the presence of two characteristic functional group.# IR suggests the presence of two characteristic functional groups. Carbonyl group with IR peak at 1710 cm-1. Hydroxyl group with IR peak in the range of 3400- 2500 cm-1. # Carbon NMR suggests presence of 7 different types of carbons. # Proton NMR suggests presence of of a total of 9 hydrogen atoms. # There is probably a carboxylic acid group in the molecule. # The 2 signals with chemical shift in the range of 7 to 8.2 ppm in proton NMR suggest the presence of benzene ring. # These two signals suggest that there is a substitution at the para position. # The splitting pattern of the peak at 2 ppm and around 5 ppm suggest there is a 1-bromo ethyl chain substitution at the para position. Here is the structure of the molecule.