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m= 5 kg 3m 40° 200 hị (me Va = 2.0 m/s hạ= 0 m At 20° past the lowest point, the rope breaks sending the mass on a projectile trajectory. Theoretical: Find the speed of the mass at the breaking point using the energy method. Find the maximum height above the breaking point that the mass will achieve using the energy method. 3m

m= 5 kg 3m 40° 200 hị (me Va = 2.0 m/s hạ= 0 m At 20° past the lowest point, the rope breaks sending the mass on a projectile trajectory. Theoretical: Find the speed of the mass at the breaking point using the energy method. Find the maximum height above the breaking point that the mass will achieve using the energy method. 3m

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For the first part of the problem I got the velocity to be 3.77m/s which I think is correct. The second part I am a bit confused with. 

 

From what I think it would be 

Ki=Kf+Ugf

(1/2)(5)(3.77)=(1/2)(5)(?vf?)+(5)(9.8)(H)

I want to find the H but I feel I also need the Vf. Would the Vf be 0 because it is at rest at the highest point? but wouldnt it still have a forward velocity. Does that mean I have to split up everything into X and Y components? 

**Part B:** A diagram shows a pendulum with a mass \( m = 5 \, \text{kg} \) suspended from a string of length \( 3 \, \text{m} \). The pendulum swings and reaches a position where the rope makes a \( 40^\circ \) angle with the vertical. At this point, the initial height \( h_i \) is considered, with \( v_a = 2.0 \, \text{m/s} \). The mass swings to a position \( 20^\circ \) past the lowest point, where the rope breaks, sending the mass on a projectile trajectory. The final height at the breaking point is denoted as \( h_f = 0 \, \text{m} \), and the velocity at the breaking point is \( v_b \). **Theoretical Objectives:** - Find the speed of the mass at the breaking point using the energy method. - Find the maximum height above the breaking point that the mass will achieve using the energy method.
Transcribed Image Text:**Part B:** A diagram shows a pendulum with a mass \( m = 5 \, \text{kg} \) suspended from a string of length \( 3 \, \text{m} \). The pendulum swings and reaches a position where the rope makes a \( 40^\circ \) angle with the vertical. At this point, the initial height \( h_i \) is considered, with \( v_a = 2.0 \, \text{m/s} \). The mass swings to a position \( 20^\circ \) past the lowest point, where the rope breaks, sending the mass on a projectile trajectory. The final height at the breaking point is denoted as \( h_f = 0 \, \text{m} \), and the velocity at the breaking point is \( v_b \). **Theoretical Objectives:** - Find the speed of the mass at the breaking point using the energy method. - Find the maximum height above the breaking point that the mass will achieve using the energy method.
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