LU Factorization Method Example 2 P2 Use Cholesky's LU factorization method to solve the system 16x1 – 12x2 – 12X3 – 16x, = 16 %3D -12x1 + 25x,+ X3 – 4x4 = – 68 -12x1 + X2 + 17x3 + 14x4 = – 20 A=LLT %3! -16x1 – 4x2 + 14x3 + 57x4 = 158 16 12 -12 a b dg O e e h 0 ofi a 000 12 25 |-4 be o 0 defo 17 14 - 16 -4 14 57. ー12 1 000

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Chapter2: Second-order Linear Odes
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LU Factorization Method
Example 2
P2 Use Cholesky's LU factorization method to solve the system
16х1 — 12х, — 12х; — 16х, %3D 16
-12x1 + 25x, + X3 - 4x4 = – 68
-12x1 + X2 + 17x3 + 14x4 = – 20
A= LLT
-16x1 – 4x2 + 14x3 + 57x, = 158
16 12 -12
a o O O
a b d
bco0
-12
17 14
defo
0 of
- 16
-4 14 57.
Transcribed Image Text:LU Factorization Method Example 2 P2 Use Cholesky's LU factorization method to solve the system 16х1 — 12х, — 12х; — 16х, %3D 16 -12x1 + 25x, + X3 - 4x4 = – 68 -12x1 + X2 + 17x3 + 14x4 = – 20 A= LLT -16x1 – 4x2 + 14x3 + 57x, = 158 16 12 -12 a o O O a b d bco0 -12 17 14 defo 0 of - 16 -4 14 57.
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