LTE lI. 9:.0 A docs.google.com Lläi 4 The IR spectrum of methyl salicylate shows absorption bands at 3300, 3050,2990, 1700, 1590 and 1540 cm-1. Which of these bands are due to which of the following groups?C=O, CH3, 0-H and aromatic ring Choose the functional groups with corresponding wave numbers 3050 1590 2990 1700 3300 and cm-1 cm-1 cm-1 1540 cm-1 Stretching for (C=0) group Stretching for (CH3) group Stretching for aromatic ring Stretching for(0-H) group Lli 4 Which is the correct order of increasing the stretching vibrations of: (1) C-H (alkane), (2) O-H (alcohol), (3) (C=O (ketone), and (4) C=C (alkyne (3) < (4) < (1) < (2) O (3) < (4) < (2) < (1) (4) < (3) < (1) < (2) (4) < (3) < (2) < (1)

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O LTE lI.
9:.0
A docs.google.com
Lläi 4
The IR spectrum of methyl salicylate
shows absorption bands at 3300,
3050,2990, 1700, 1590 and 1540 cm-1.
Which of these bands are due to which
of the following groups?C=D0, CH3, 0-H
and aromatic ring
Choose the functional groups with corresponding
wave numbers
3050
1590
2990
1700
3300
and
cm-1
cm-1
cm-1
1540
cm-1
Stretching
for (C=0)
group
Stretching
for (CH3)
group
Stretching
for
aromatic
ring
Stretching
for(0-H)
group
Llä 4
Which is the correct order of
increasing the stretching vibrations of:
(1) C-H (alkane), (2) O-H (alcohol), (3)
(C=O (ketone), and (4) C=C (alkyne
(3) < (4) < (1) < (2) O
(3) < (4) < (2) < (1)
(4) < (3) < (1) < (2)
(4) < (3) < (2) < (1)
O O O
Transcribed Image Text:O LTE lI. 9:.0 A docs.google.com Lläi 4 The IR spectrum of methyl salicylate shows absorption bands at 3300, 3050,2990, 1700, 1590 and 1540 cm-1. Which of these bands are due to which of the following groups?C=D0, CH3, 0-H and aromatic ring Choose the functional groups with corresponding wave numbers 3050 1590 2990 1700 3300 and cm-1 cm-1 cm-1 1540 cm-1 Stretching for (C=0) group Stretching for (CH3) group Stretching for aromatic ring Stretching for(0-H) group Llä 4 Which is the correct order of increasing the stretching vibrations of: (1) C-H (alkane), (2) O-H (alcohol), (3) (C=O (ketone), and (4) C=C (alkyne (3) < (4) < (1) < (2) O (3) < (4) < (2) < (1) (4) < (3) < (1) < (2) (4) < (3) < (2) < (1) O O O
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