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Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1- p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. 0.01 ре (1- р)е 0 (1– p)e 02 -20 -0.2 (A) pe 100 10,000 100 10,000 pe (1– p)e-0.01 -20 (1– p)e 02 (B) ре 100 10,000 100 10,000 20 (1– p)e02 -0.01 ре (1- р)е 001 ре (C) 100 10,000 100 10,000 Pel 100 (1– p)e-001 (1- p)e02 -20 --0.2 (D) ре 10,000 100 10,000 0.01 e р. 100' 10,000 -20 (E) e 0.2 100 10,000

Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1- p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. 0.01 ре (1- р)е 0 (1– p)e 02 -20 -0.2 (A) pe 100 10,000 100 10,000 pe (1– p)e-0.01 -20 (1– p)e 02 (B) ре 100 10,000 100 10,000 20 (1– p)e02 -0.01 ре (1- р)е 001 ре (C) 100 10,000 100 10,000 Pel 100 (1– p)e-001 (1- p)e02 -20 --0.2 (D) ре 10,000 100 10,000 0.01 e р. 100' 10,000 -20 (E) e 0.2 100 10,000

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1- p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. 0.01 pe' (1– p)e0« (1– p)e 02 -20 -0.2 (A) pe 100 10,000 100 10,000 -20 (1– p)e 02 ре (1- рје 001 10,000 (B) ре 100 100 10,000 pe, (1- p)e 0.01) 20 (1– p)e02 (C) ре ре 100 10,000 100 10,000 Pel 100 (1– p)e-001 (1– p)e-02 -20 (D) ре 10,000 100 10,000 e-0.2 + 100 10,000 e e 0.01 -20 (E) р. + 100 10,000
Transcribed Image Text:Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1- p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. 0.01 pe' (1– p)e0« (1– p)e 02 -20 -0.2 (A) pe 100 10,000 100 10,000 -20 (1– p)e 02 ре (1- рје 001 10,000 (B) ре 100 100 10,000 pe, (1- p)e 0.01) 20 (1– p)e02 (C) ре ре 100 10,000 100 10,000 Pel 100 (1– p)e-001 (1– p)e-02 -20 (D) ре 10,000 100 10,000 e-0.2 + 100 10,000 e e 0.01 -20 (E) р. + 100 10,000
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