Hi I asked the below question already and here was my solution in picture. But my question is, for the solution below in the 3rd and 4th line how did you get to f(103) and f(104) and knew the root lied between there. If you could explain that to me I would really appreciate it thanks very much."Hi, I am looking to solve this, what was a differential equation please, through the fixed point iterative method is what I have been told to solve it but also another iterative method is sufficient, and the answer should be around 100.Looking to solve for t please91.4521 + 0.01t*(1 - e^(-700/t))*(-88.544) = 0Thank you" 21:48 *46 ull 50%Answered: solve it but also a..bartleby.com= bartlebyE Q&AMath / Advanced Math / Q&A Library / solve it but also anot...solve it but also another iterative method...Get live help whenever youTry bartlebytutor todayneed from online tutors!-700O fit) = 91.4521+ 0.01 t(hhs:88-).1-e )(-.544)- 700= 91.4521 - 08544.t.(103) = 0.3537519 >o= - 0.5237451 0. Root lies between 103. and.104.- tn-f'(tn)1,By Newton Raphson method, tnti'chooring= L03- 7o0700619.808.e-0.88541st iteratibnf(to) = f(103) = 0.3537519f!lto) = fl(103)- 0.8777217fLto)f.( 103)* t = to103f(103)0.3537519%3D103 -10 3. 40303422nd iterafanf( 103.4030342)f'(103.4030312)103.4030342+2= thf'lti)t2 =103.4030755gd iterafimf( 103.4030755)fl(103.4030755)- 103.403055-(24)103.4030755.103.4030755Hence the root of f lt) isII

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Answered: Looking to solve for t please 91.4521…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Hi I asked the below question already and here was my solution in picture. But my question is, for the solution below in the 3rd and 4th line how did you get to f(103) and f(104) and knew the root lied between there. If you could explain that to me I would really appreciate it thanks very much.

"Hi, I am looking to solve this, what was a differential equation please, through the fixed point iterative method is what I have been told to solve it but also another iterative method is sufficient, and the answer should be around 100.

Looking to solve for t please

91.4521 + 0.01t*(1 - e^(-700/t))*(-88.544) = 0

Thank you"

21:48 *
46 ull 50%
Answered: solve it but also a..
bartleby.com
= bartleby
E Q&A
Math / Advanced Math / Q&A Library / solve it but also anot...
solve it but also another iterative method...
Get live help whenever you
Try bartleby
tutor today
need from online tutors!
-700
O fit) = 91.4521+ 0.01 t
(hhs:88-).
1-e )(-.544)
- 700
= 91.4521 - 08544.t.
(103) = 0.3537519 >o
= - 0.5237451 0
. Root lies between 103. and.104.
- tn-
f'(tn)
1,
By Newton Raphson method, tnti'
chooring
= L03
- 7o0
700
619.808.e
-0.8854
1st iteratibn
f(to) = f(103) = 0.3537519
f!lto) = fl(103)
- 0.8777217
fLto)
f.( 103)
* t = to
103
f(103)
0.3537519
%3D
103 -
10 3. 4030342
2nd iterafan
f( 103.4030342)
f'(103.4030312)
103.4030342
+2= th
f'lti)
t2 =
103.4030755
gd iterafim
f( 103.4030755)
fl(103.4030755)
- 103.403055-
(24)
103.4030755.
103.4030755
Hence the root of f lt) is
II

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