Given the initial condition y(1) = 4, what is the particular solution of the equation y' = y (2x + 3)? ○ y = ex²+3x+0.073 y = ex²+3x -0.073 y = 0.073 ex²+3x y = ex² + 3x + 0.073
Given the initial condition y(1) = 4, what is the particular solution of the equation y' = y (2x + 3)? ○ y = ex²+3x+0.073 y = ex²+3x -0.073 y = 0.073 ex²+3x y = ex² + 3x + 0.073
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Given the initial condition y(1) = 4, what is the particular solution of the equation y' = y (2x + 3)?
= ex²+3x+0.073
y =
○ y = et²+3x - 0.073
○ y = 0.073ex²+3x
○ y = ex²+3x +0.073](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F883933e7-6864-477d-8bb2-712659e12b95%2F62ca0b19-bf16-400d-bfb3-4f92fa2205cf%2F3olrym_processed.png&w=3840&q=75)
Transcribed Image Text:Given the initial condition y(1) = 4, what is the particular solution of the equation y' = y (2x + 3)?
= ex²+3x+0.073
y =
○ y = et²+3x - 0.073
○ y = 0.073ex²+3x
○ y = ex²+3x +0.073
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