Look up and plot some fission cross section data for some NMAC-relevant nuclides (235U,238 U, and 239Pu). Why is each nuclide fissile or fissionable? Explain the rapidly oscillatingregion of the plots. Pick one of these peaks. Which isotope and energy did you choose?What is the lifetime of the resonance?

Answered: Image /qna-images/answer/c9971a0e-cbcb-4a9c-bb62-2cb4f48b0dfe.jpg

Answered: Look up and plot some fission cross…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The naturally occurring radioactive isotope 232Th does not make good fission fuel, because it has an even number of neutrons; however, it can be bred into a suitable fuel (much as 238U is bred into 239P ). Confirm that the final nucleus has an odd number of neutrons, making it a better fission fuel.
Calculate the binding energy per nucleon (in J) for 108 and 118. The atomic masses are 10.012937 u for 108, and 11.009306 u for 113. (Enter unrounded values. Assume that the mass of H = 1.007825 u, mp = 1.007275 u, mn = 1.008666 u, and m = 0.000549 u, respectively.) 10B -1.824e-14 118 -2.3920-14 XJ/nucleon XJ/nucleon Need Help? Read It Supporting Materials Periodic Table Constants & Factors Supplemental Data
Ruthenium-106 (106Ru) is used to treat melanoma in the eye. This isotope decays by β– emission with a half-life of 373.59 days. One source of the isotope is reprocessed nuclear reactor fuel. How many protons and neutrons does the 106Ru nucleus contain? Identify the missing daughter nucleus in the β– emission decay of 106Ru below. How many years after 106Ru is implanted in the eye does it take for its decay rate (or activity) to be reduced to 27.5% of the initial decay rate? Use 1 year = 365 days.
Write a balanced nuclear reaction for the following: 234 Pa + 4 He +, 91 2 When balancing the nuclear reaction, explain the following: • How does the Law of Conservation of Matter dictate what the daughter nuclide is? • How do we calculate the atomic mass and atomic number for the daughter nuclide? • Where do we look up what the new daughter nuclide element is?
Topic: Nuclear Chemistry
a) Mrs. Price's son, Liam is currently working as a boilermaker at the Darlington Nuclear Power plant. He is working with Uranium-237 which has a half-life of 13.75 days. What mass of an initial sample of 567.5g of uranium-237 would remain after 56 days? b) Write the complete reaction for the decay of Po-210 if it undergoes 2 consecutive alpha decay followed by a beta decay followed by another alpha decay.
1. The disintegration energy of the decay30 P15 by position emission is 4.30 Mev. The daughter nuclide, Si has a mass of 29.97396 u. What is the mass of 30P15 ? 2. The nuclide 192Pt78decays to 1880s76 by alpha emission. The mass of 192Pt78 is 191.96146 u and the mass of 188Os76 is 187.9560 u. Calculate the energy effect accompanying the decay. 3. Calculate the energy released by the fusion process3He + 3He → 4He2 + 2H. The masses of the pertinent atoms are: 3He2 = 3.01603u. 4He2 = 4.00260u. 1H2 = 1007825u.
Q¹
12. Calculate the nuclear binding energy per one nucleon for the Be-8 isotope (eight nucleons). Here are some helpful data: {B.E = Am .c2 c=3.00 x 108 m/s and I J= kg.m2/s2} 1.32931 x 10-23 g 1.67262158 × 10–24 g 1.67492716 x 10–24 g Actual mass of Be- 8 proton mass neutron mass a) 1.2035 x 10–6 J/nucleon c) 1.092263 x 10–12 J/nucleon b) 1.092263 x 10–9 J/nucleon d) 8.7381 x 10–12 J/nucleon
A student is surprised by her work. She feels that the nuclear binding energy is high for oxygen-16. Her work is as follows: Part 1: One neutron's mass is 1.008665 amu, while one proton's mass is 1.007276 amu. In oxygen - 16 there are 8 protons and 8 neutrons with a total mass of 16.127528 amu. (1.007276x8)+(1.008665x8)=16.127528 Part 2: Because the mass of oxygen-16 is 15.994915 amu, the difference between the mass of an atom and the sum of its protons and neutrons is the mass defect. The mass defect for oxygen-16 is 0.132613 amu. 16.127528-15.994915 0.132613 Part 3: The missing mass in oxygen-16 is converted to the nuclear binding energy using Einstein's equation E = mc². The amount of energy is 1.19x1016 J, which I think is too high. E = mc² = (0.132613) × (3.00 x 108)2=1.193×1016 J Which part of the solution was there an error? a) Parts 2 and 3. b) Part 3 only. c) Parts 1 and 2. d) No error.
Enter your answer in scientific notation. Be sure to answer all parts. Calculate the nuclear binding energy (in J) and the binding energy per nucleon for the following isotope: 209 Bi 83 (208.9804 amu) Nuclear binding energy = x 10 Binding energy per nucleon = x 10 J/nucleon

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